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iogann1982 [59]
3 years ago
14

A chemical company mixes pure water with their premium antifreeze solution to create an inexpensive antifreeze mixture. The prem

ium antifreeze solution contains 70% pure antifreeze. The company wants to obtain 140 gallons of a mixture that contains 20% pure antifreeze. How many gallons of water and how many gallons of the premium antifreeze solution must be mixed
Mathematics
1 answer:
snow_tiger [21]3 years ago
7 0

Answer:

40 gallons of premium antifreeze and 100 gallons of water should be used to obtain 140 gallons of a mixture that contains 20% pure antifreeze.

Step-by-step explanation:

Since a chemical company mixes pure water with their premium antifreeze solution to create an inexpensive antifreeze mixture, and the premium antifreeze solution contains 70% pure antifreeze, and the company wants to obtain 140 gallons of a mixture that contains 20% pure antifreeze, to To determine how many gallons of water and how many gallons of the premium antifreeze solution must be mixed, the following calculation must be performed:

50 x 0.7 + 50 x 0 = 35

40 x 0.7 + 60 x 0 = 28

30 x 0.7 + 70 x 0 = 21

29 x 0.7 + 71 x 0 = 20.3

28.57 x 0.7 + 71.43 x 0 = 20

140 x 0.2857 = 40

Therefore, 40 gallons of premium antifreeze and 100 gallons of water should be used to obtain 140 gallons of a mixture that contains 20% pure antifreeze.

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