Answer:
I believe that you would shade the one in the bottom right corner, but you might want to double check
Step-by-step explanation:
you take a (x,y) coordinate from each quadrant and plug in the numbers to see if the equation is correct. If it isn't, you do not shade that quadrant.
so for example, y<1/2 x
say your coordinate is (2,1)
you plug in the numbers so that it looks like 1>1/2×2.
1/2 × 2 is 1,
so therefore this equation is incorrect because 1 is not greater than one.
Answer:
31.6 sq.in i got by using 2pier formula
To find the maximum or minimum value of a function, we can find the derivative of the function, set it equal to 0, and solve for the critical points.
H'(t) = -32t + 64
Now find the critical numbers:
-32t + 64 = 0
-32t = -64
t = 2 seconds
Since H(t) has a negative leading coefficient, we know that it opens downward. This means that the critical point is a maximum value rather than a minimum. If we weren't sure, we could check by plugging in a value for t slightly less and slighter greater than t=2 into H'(t):
H'(1) = 32
H'(3) = -32
As you can see, the rate of change of the object's height goes from increasing to decreasing, meaning the critical point at t=2 is a maximum.
To find the height, plug t=2 into H(t):
H(2) = -16(2)^2 +64(2) + 30 = 94
The answer is 94 ft at 2 sec.
2nd opinion that’s your answer
<span>written in standard form
</span><span>
7.12 x 10^-3 = 0.00712
hope it helps</span>
