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g100num [7]
3 years ago
14

In XYZ, X = 57 cm, z = 54 cm and ZZ=112°. Find all possible values of ZX, to the nearest degree

Mathematics
2 answers:
Alik [6]3 years ago
7 0

Answer:

No Possible Triangles

Step-by-step explanation:

Deltamath

Vladimir79 [104]3 years ago
3 0

Answer:

102

Step-by-step explanation:

sinA/a = sinB/b

sin x /57=sin 112/54

0.9786941

sin ^ -1 (0.786941)=78

180- 78=102

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Hi, can someone please help, and possibly explain the answer please.
mr_godi [17]

Answer:

x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}

Step-by-step explanation:

Quadratic formula: x=\frac{-b\±\sqrt{b^2-4ac} }{2a} when the equation is 0=ax^2+bx+c

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1=-2x+3x^2+1

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x=\frac{-b\±\sqrt{b^2-4ac} }{2a}\\x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}

I hope this helps!  

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