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Xelga [282]
3 years ago
10

Look at the Employee Time Card for

Mathematics
1 answer:
pshichka [43]3 years ago
8 0
I believe it’s 84.50
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-3x -4y = 20 x - 10y =16 if (x, y) is the solution to the system of equations above what is the value of x?
balu736 [363]
Multiply first equation by -5 and 2nd by 2, add them

15x+20y=-100
<u>2x-20y=32 +</u>
17x+0y=-68

17x=-68
divide both sides by 17
x=-4
 

the x value is -4
6 0
4 years ago
Please help me with this.
Tom [10]

Answer:

28.26

Step-by-step explanation:

Area of a circle = pi (radius)^2 so...

A=3.14(9) = 28.26, which is your first choice

7 0
4 years ago
Please help will mark Brainly!
MakcuM [25]

Answer:

The table doesn't display a linear relationship because the slope doesn't stay constant throughout the whole table.

7 0
4 years ago
Observe that equation (3) has constant coefficients. If y1(x) and y2(x) form a fun- damental set of solutions of equation (3), s
WARRIOR [948]

The equations (2) and (3) you referred to are unavailable, but it is clear that you are trying to show that two set of solutions y1 and y2, to a (second-order) differential equation are solutions, and form a fundamental set. This will be explained.

Answer:

SOLUTION OF A DIFFERENTIAL EQUATION.

Two functions y1 and y2 are set to be solutions to a differential equation if they both satisfy the said differential equation.

Suppose we have a differential equation

y'' + py' + qy = r

If y1 satisfies this differential equation, then

y1'' + py1' + qy1 = r

FUNDAMENTAL SET OF DIFFERENTIAL EQUATION.

Two functions y1 and y2 are said to form a fundamental set of solutions to a second-order differential equation if they are linearly independent. The functions are linearly independent if their Wronskian is different from zero.

If W(y1, y2) ≠ 0

Then solutions y1 and y2 form a fundamental set of the given differential equation.

7 0
3 years ago
Question 13 of 47
ser-zykov [4K]

Answer:

d. 6-19i

Step-by-step explanation:

(5-8i)+(1-11i)

<u>Step 1: Combine like terms within the parenthesis. There are </u><u>no </u><u>like terms within the parenthesis. So, drop the parenthesis and move on to the next step. </u>

(<em>Remember!! If you would have had a negative sign in front of either parenthesis, you would need to distribute out the negative sign).</em>

5 - 8i + 1 - 11i

<u>Step 2: Now add like terms.</u>

5 + 1 - 8i - 11i

6 - 19i

<em>You can't combine any more like terms, so this is your final answer.</em>

6 - 19i

5 0
3 years ago
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