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olasank [31]
3 years ago
15

Write the slope and y-intercept of each equation.

Mathematics
1 answer:
ioda3 years ago
3 0

Answer:

okay here goes.

Step-by-step explanation:

1. slope = -5  and y-intercept is (0,6)

2. slope = 3 and  y-intercept is (0,-2)

3. -2 and (0,-4)

4. 8 and (0,1)

5. 5 and (0,-3)

6. -3 and (0,-9)

7. 7 and (0,2)

8. -1 and (0,6)

9. -4 and (0,7)

10. -6 and (0,-8)

11. 8 and (0,-5)

12. 9 and (0,3)

You owe me. That took a long time to write.

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A model rocket is launched from a roof into a large field. The path of the rocket can be modeled by the equation
Alexxx [7]
Ok

y=-0.04x^2+8.3x+4.3
when the rocket reaches the ground (when height=0, ie when y=0), then the rocket will land, find the x coordinate

set y=0
0=-0.04x^2+8.3x+4.3
use quadratic formula
if you have ax^2+bx+c=0, then
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}
a=-0.04
b=8.3
c=4.3
x=\frac{-8.3+/- \sqrt{8.3^{2}-4(-0.04)(8.3)} }{2(-0.04)}
x=208.017 or -0.516785
xrepresents horizontal distance
you cannot have a negative horizontal distance unless you fired and theh wind blew it backwards
therefor x=280.017 is the answer
208.02 m


7 0
3 years ago
In the adjoining figure O is the centre of the circle the tangent to the circle of radius 6 cm from the exterior point P of the
slamgirl [31]

Answer:

Let P be the external point. O be the origin. join O and P get OP and nearest point on the circle from P be A.

Let Q be the point onthe circle  in which, tangent make 90° with radius at Q.

PQ = 8 and OQ = 6

we get a right angled triangle  PQO right angled at Q.

so, OP^2 = OQ^2 + PQ^2= 8^2 + 6^2 = 64 + 36 =1==

therefore OP =10cm

we need nearest point from P, which is PA

PA = OP - OA= 10 -6=4cm

7 0
3 years ago
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3241004551 [841]

Answer:

(0,0)

Step-by-step explanation:

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Answer:

C. \frac{1}{8}

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