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givi [52]
3 years ago
9

The area of a parallelogram is 8x^2+2x-6 and it's height is 2x+2. What is the base of the parallelogram?​

Mathematics
1 answer:
ZanzabumX [31]3 years ago
4 0

Answer:

4x - 6

Step-by-step explanation:

Remember the formula for finding the area of a parallelogram;(base)*(height)=(area)

Manipulate the equation such that it is solved for the base;

(base)=\frac{(area)}{(height)}

So the equation that needs to be solved is;

\frac{(8x^{2} + 2x - 6 )}{(2x + 2)}

Set up the division problem and solve;

              _____<u>4x - 6</u>___

2x + 2     | 8x^{2} + 2x - 6

             -(8x^{2}+8x)<u />

                ________

                       -6x - 6

                      + (6x + 6 )

                      ________

                              0

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