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sineoko [7]
3 years ago
13

Is 8 a whole number?​

Mathematics
2 answers:
sesenic [268]3 years ago
6 0

Answer:

Yes.

Step-by-step explanation:

krok68 [10]3 years ago
5 0
Answer: Yes 8 is a whole number
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Jordan said 60% of 150 people is 80 people.Is his answer correct?Explain why or why not.
jek_recluse [69]
150 times .6 is 90 not 80 that is why Jordan is incorrect
6 0
3 years ago
Read 2 more answers
Solve this quadratic form 3x-2x²=7 this is grade 9​
Pani-rosa [81]

Answer:

x

=

3

±

i

√

47

4

x=3±i474

Step-by-step explanation:

7 0
4 years ago
Strontium-90 has a half-life of about 29 years. After 65 years, about how many grams of a 25-gram sample will remain?
konstantin123 [22]

Answer:

Ending Amount = Beginning Amount / 2 ^ n

where 'n' = number of half-lives n = 65 / 29 = 2.2413793103

Ending Amount = 25 g / 2^2.2413793103

Ending Amount = 25 / 4.7284892286

Ending Amount = 5.2871009727  g = 5.29 g (rounded)

Step-by-step explanation:

3 0
3 years ago
Plz help I have no idea how to answer it​
saveliy_v [14]

5. Answer: see explanation

<u>Step-by-step explanation:</u>

If the roots are m and 3m, then x = m and x = 3m

⇒ x - m = 0    and      x - 3m = 0

⇒ (x - m)(x - 3m) = 0

⇒ x² - 4mx + 3m² = 0

Since x² + px + q = 0   then  p = -4m   and q = 3m²

3p² = 3(-4m)²               16q = 16(3m²)

      = 3(16m²)                      = 48m²

      = 48m²

3p² = 48m² = 16q     ⇒           3p² = 16q

**********************************************************************************************

6. Answer: 8 or 18

<u>Step-by-step explanation:</u>

The Area of the entire rectangle (A = L × w) is 12 × 10 = 120

The Area of the shaded region is 72, so the Area of the non-shaded region is 120 - 72 = 48.

There are two non-shaded triangles.

  • Bigger non-shaded Δ: L = 12-x, w = 10  ⇒ A = \dfrac{10(12-x)}{2}
  • Smaller non-shaded Δ: L = x, w = x ⇒ A=\dfrac{x(x)}{2}

Combine the Areas of both triangles and set it equal to the Area of the non-shaded region:

\dfrac{x(x)}{2}+\dfrac{10(12-x)}{2}=48\\\\\\\dfrac{x^2}{2}+\dfrac{120-10x}{2}=48\\\\\\\dfrac{x^2-10x+120}{2}=48\\\\\\x^2-10x+120=96\\\\x^2-10x+24=0\\\\(x-4)(x-6)=0\\\\x - 4 = 0\quad or\quad x-6=0\\x=4\qquad or\qquad x=6\\\\\text{Based on the image provided, it appears that the x-value will be the}\\\text{smallest of the two possible solutions (4), but both solutions are valid.}

Area of ΔBEF:

\text{when x = 4, A =}\ \dfrac{4(4)}{2}=\dfrac{16}{2}=8\\\\\\\text{when x = 6, A =}\ \dfrac{6(6)}{2}=\dfrac{36}{2}=18

5 0
3 years ago
Is this right? if not, can you please fix it? ​
Viktor [21]

Answer:

(x+1)

Step-by-step explanation:

6x^2 -6         3-3x

-------------- ÷ ---------

8x^2 +8x       4x^2 +4x

Copy dot flip

6x^2 -6         4x^2 +4x

-------------- *---------

8x^2 +8x       3-3x

Factor

6(x^2-1)        4x(x+1)

-------------- * ---------

8x(x+1)       3(x-1)

6(x-1)(x+1)       4x(x+1)

-------------- * ---------

8x(x+1)       3(x-1)

Cancel like terms

2(x-1)           (x+1)

-------------- * ---------

2                   (x-1)

    (x+1)

                   

5 0
3 years ago
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