21 billion is how much more than 9.8 billion write the answer in scientific notation

Define an action adder :: io () that reads a given number of integers from the key board, one per line, and displays their sum.

aleksandrvk [35]

The program is an illustration of loops

<h3>What are loops?</h3>

Loops are program statements that are used to perform repetition

<h3>The main program</h3>

The program written in Python, where comments are used to explain each line is as follows:

#This initializes sum to 0

summ = 0

#This gets input for the first number

num = int(input())

#This is repeated while num is not -1

while num!= -1:

#This calculates the sum

summ+=num

#This gets input for the num

num = int(input())

#This prints the sum

print(summ)

Read more about loops at:

brainly.com/question/16397886

4 0

3 years ago

Melissa made a paperweight. The paperweight is a rectangular prism. She painted the outside surface of the paperweight.

Alex777 [14]

Surface area = (5*(12))+2(4*3)

7 0

3 years ago

What is the name of the fee charged by a financial institution for withdrawing money from an account before the maturity date?

LenaWriter [7]

This fee is typically called an early withdrawal fee or early withdrawal penalty.

8 0

3 years ago

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The sum of four consecutive terms of an arithmetic progression is 32 and the ratio of product of the first and the last term to

OverLord2011 [107]

The four consecutive terms are 2,6,10,14.

Explanation:

Let the four consecutive terms of an arithmetic progression be (a - 3d), (a - d),(a + d), (a + 3d)

It is given that the sum of four consecutive terms is 32.

Thus, adding all the four consecutive terms, we have,

$\begin{array}{r}{a-3 d+a-d+a+d+a+3 d=32} \\{4 a=32} \\{a=8}\end{array}$

Thus, the value of a is 8.

It is also given that the ratio of the product of first and last term to the product of the two middle terms is 7:15. Thud, we have,

$\frac{(a-3d)(a+3d)}{(a-d)(a+d)} =\frac{7}{15}$

Simplifying the terms, we have,

$\begin{aligned} \frac{a^{2}-9 d^{2}}{a^{2}-d^{2}} &=\frac{7}{15} \\ 15\left(a^{2}-9 d^{2}\right) &=7\left(a^{2}-d^{2}\right) \\ 15 a^{2}-135 d^{2} &=7 a^{2}-7 d^{2} \\ 8 a^{2} &=128 d^{2} \end{aligned}$

Now, substituting a = 8, we have,

$\begin{aligned} 8(64) &=128 d^{2} \\ 512 &=128 d^{2} \\ 4 &=d^{2} \\ 2 &=d \end{aligned}$

Thus, the value of d is 2.

Now, we shall substitute the value of a and d in the terms (a - 3d), (a - d),(a + d), (a + 3d), we get, the four consecutive terms.

Thus, the four consecutive terms are 2,6,10,14.

8 0

3 years ago

In the given figure, find the value of x and y ?<br>

mina [271]

Step-by-step explanation:

please mark me as brainlest

6 0

3 years ago

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