Answer:
b
Step-by-step explanation:
 dbhdkcnsbnadjfmmfejsdbfjkgkf
 
        
             
        
        
        
Answer:
3 &4
Step-by-step explanation:
 
        
             
        
        
        
Answer:
At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.
Step-by-step explanation:
Hello!
Considering the dependent variable:
Y: Ductility in steel.
And the independent variable:
X: Carbon content of the steel.
The linear regression was estimated and a prediction interval was calculated.
The prediction interval is calculated to predict a value that the variable Y (response variable) can take for a given value of the variable X (predictor variable) in the definition range of the linear regression line. Symbolically [Y/X=
]
In this case 95% prediction interval for Y/X=0.5
At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.
I hope it helps!
 
        
             
        
        
        
It is true that they are congruent.
Side JK and PM are congruent to each other
JK = 25 
PM is divided into two measurements=19 and 6.
So PM is 19 + 6 = 25 
Therefore JK = PM
        
             
        
        
        
4x = 32 - 2x
Add -2x (or subtract 2x) from each side
2x = 32
Divide both sides by 2
x = 16