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Tom [10]
4 years ago
9

Compare 16 cups to 1 gallon

Mathematics
1 answer:
aleksandrvk [35]4 years ago
5 0
Hi there!

Since there are 16 cups in a gallon, 

16 cups = 1 gal

Hope this helps!
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If XX is a binomial random variable, compute the mean, the standard deviation, and the variance for each of the following cases:
Liula [17]

Answer:

(a) The mean, variance and standard deviation of <em>X </em>are 1.60, 0.96 and 0.98 respectively.

(b) The mean, variance and standard deviation of <em>X </em>are 3.20, 0.64 and 0.80 respectively.

(c) The mean, variance and standard deviation of <em>X </em>are 1.50, 0.75 and 0.87 respectively.

(d) The mean, variance and standard deviation of <em>X </em>are 4.00, 0.80 and 0.89 respectively.

Step-by-step explanation:

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The mean, variance and standard deviation of <em>X</em> are:

\mu=np\\\sigma^{2}=np(1-p)\\\sigma=\sqrt{np(1-p)}

(a)

For <em>n</em> = 4 and <em>p</em> = 0.40 compute the mean, variance and standard deviation of <em>X </em>as follows:

\mu=np=4\times0.40=1.60\\\sigma^{2}=np(1-p)=4\times0.40\times(1-0.40)=0.96\\\sigma=\sqrt{np(1-p)}=\sqrt{0.96}=0.98

Thus, the mean, variance and standard deviation of <em>X </em>are 1.60, 0.96 and 0.98 respectively.

(b)

For <em>n</em> = 4 and <em>p</em> = 0.80 compute the mean, variance and standard deviation of <em>X </em>as follows:

\mu=np=4\times0.80=3.20\\\sigma^{2}=np(1-p)=4\times0.80\times(1-0.80)=0.64\\\sigma=\sqrt{np(1-p)}=\sqrt{0.64}=0.80

Thus, the mean, variance and standard deviation of <em>X </em>are 3.20, 0.64 and 0.80 respectively.

(c)

For <em>n</em> = 3 and <em>p</em> = 0.50 compute the mean, variance and standard deviation of <em>X </em>as follows:

\mu=np=3\times0.50=1.50\\\sigma^{2}=np(1-p)=3\times0.50\times(1-0.50)=0.75\\\sigma=\sqrt{np(1-p)}=\sqrt{0.75}=0.87

Thus, the mean, variance and standard deviation of <em>X </em>are 1.50, 0.75 and 0.87 respectively.

(d)

For <em>n</em> = 5 and <em>p</em> = 0.80 compute the mean, variance and standard deviation of <em>X </em>as follows:

\mu=np=5\times0.80=4.00\\\sigma^{2}=np(1-p)=5\times0.80\times(1-0.80)=0.80\\\sigma=\sqrt{np(1-p)}=\sqrt{0.80}=0.89

Thus, the mean, variance and standard deviation of <em>X </em>are 4.00, 0.80 and 0.89 respectively.

6 0
3 years ago
Find slope of given two points <br> (-14,3) (7,-9)
Vesna [10]

Answer:

5/4

Step-by-step explanation:

(y2 - y1) / (x2 - x1)

(-9 + 14) / (7 - 3)

5/4

6 0
3 years ago
Find the value of h in this triangle. Please and Thank you!
Dahasolnce [82]

Answer:

<em>h=</em> 10m

Step-by-step explanation:

<em>1/2x12x18.2=109.2m squared</em>

<em>then u divide it by 21.8</em>

<em>109.2m2/21.8m/ 1/2=10m</em>

<em>h=10m</em>

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3 years ago
How to find the median on a dot plot?
pickupchik [31]

Answer:

In order to find the median of the data you take every value and order it from least to greatest. When you do this make sure you write a number the correct amount of times. for example if there are 4 dots above 6 on the dot plot then you need to make sure you write 6 4 times. After you have all the data from least to greatest find the number in the middle. that is the median.


4 0
4 years ago
Select the equivalent expression.
olasank [31]

Answer:

Answer Choice 'A' would be correct.

7 0
3 years ago
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