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ivann1987 [24]
4 years ago
9

The mall is 4.72 kilometers from Julie’s house and 1.83 kilometers from Taylor’s house. How much farther does Julie live from th

e mall than Taylor?
Mathematics
2 answers:
blondinia [14]4 years ago
7 0
Julies lives 2.89 kilometers more from the mall than Taylor. 
inn [45]4 years ago
4 0
Julie lives 2.89 kilometers further from the mall than Taylor. To get this answer, simply find the difference of the distances between the mall to Julie’s house and Taylor’s house.
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6
Veseljchak [2.6K]
The answer is i think 262.08 miles
8 0
3 years ago
Read 2 more answers
-25+t=-44 solve using addition principle. The solution is t=
love history [14]

Explanation:

First, add by 25 both sides of an equation.

-25+t+25=-44+25

Then, simplify by equation and add/subtract by the numbers.

44-25=19

*The answer must be have a negative sign.

\boxed{t=-19}

Hope this helps!

Thank you!

Have a great day!

3 0
3 years ago
Read 2 more answers
The hypotenuse of a right angled triangle is 2√13 cm . If the smaller side is increased by 2 cm and the larger side is increased
White raven [17]

<em><u>Statement:</u></em>

The hypotenuse of a right angled triangle is 2√13 cm. If the smaller side is increased by 2 cm and the larger side is increased by 3 cm, the new hypotenuse will be √117 cm.

<em><u>To find out:</u></em>

The length of the larger side of the right angled triangle.

<em><u>Solution:</u></em>

Let us consider x as the smaller side and y as the larger side.

Then, in the right angled triangle,

x² + y² = (2√13)² ...(I) [By Pythagoras Theorem]

Now, if the smaller side is increased by 2 cm, then the smaller side will be (x + 2).

And if the larger side is increased by 3 cm, then the larger side will be (y + 3).

Then, in the new right angled triangle,

(x + 2)² + (y + 3)² = (√117)² [By Pythagoras Theorem]

or, x² + 2 × 2 × x + 2² + y² + 2 × 3 × y + 3² = (√117)²

or, x² + 4x + 4 + y² + 6y + 9 = (√117)²

or, x² + y² + 4x + 6y + 13 = (√117)²

Now, put the value of x² + y² from equation (I),

or, (2√13)² + 4x + 6y + 13 = (√117)²

or, (2 × 2 × √13 × √13) + 4x + 6y + 13 = (√117 × √117)

or, 52 + 4x + 6y + 13 = 117

or, 4x + 6y = 117 - 52 - 13

or, 4x + 6y = 52

or, 4x = 52 - 6y

or, x = \frac {(52 - 6y)}{4} ...(II)

Now, put the value of x of equation (II) in (I),

x² + y² = (2√13)²

or, \frac {(2704-624y +36y²)}{16} + y² = 52

or, \frac {(2704-624y +36y² + 16y²)}{16}= 52

or, 52y²-624y + 2704 = 52 × 16

or, 52y² - 624y + 2704 - 832 = 0

or, 52y² - 624y + 1872 = 0

or, 52(y² - 12y + 36) = 0

or, y²-12y +36 = 0 ÷ 52

or, y²-12y +36 = 0

or, (y)² - 2 × 6 × y + (6)² = 0

or, (y - 6)² = 0

or, y - 6=0

or, y = 6

We have taken y as the length of the larger side of the right angled triangle.

So, the length of the larger side is 6 cm.

<em><u>Answer:</u></em>

6 cm

Hope you could understand.

If you have any query, feel free to ask.

6 0
3 years ago
bag contains 15 marbles numbered from 1 to 15. Two marbles are selected from the bag at the same time. Let event E = the two num
lbvjy [14]
The numbers DO differ by 10 if they are

- 1 and 11
- 2 and 12
- 3 and 13
- 4 and 14
- 5 and 15

Each outcome technically has two ways of occurring, but since we're taking two marbles at a time, that would be the same as saying, for instance, that drawing 1 and 11 is the same as drawing 11 and 1. We only count such an event once.

So the answer is (a) 5.
7 0
3 years ago
Read 2 more answers
2^3 times 2^3+= <br> what does this eqaul
VLD [36.1K]

Answer:

36

Step-by-step explanation:

2x3 x 2x3 = 36

Sorry if this didnt help

3 0
3 years ago
Read 2 more answers
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