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3 years ago

HELP WITH MY MATH PLEASE

Mathematics

2 answers:

Cloud [144]3 years ago

7 0

The angels across from each other are the same. That makes the sides and the interior lines the same as well. So that means the lines cannot cross each other. They are parallel

galina1969 [7]3 years ago

7 0

Answer:

because im god and god is good and 9 x 10 is 99999

Step-by-step explanation:

You might be interested in

The area of the above polygon is ?<br>the answer is not 44

vitfil [10]

Check the picture below.

you really have two rectangles, a 6x10 and a 6x5, and surely you know what those areas are, so sum them up, and that's the area of the polygon.

6 0

3 years ago

The given matrix is the augmented matrix for a linear system. Use technology to perform the row operations needed to transform t

shtirl [24]

Answer:

$x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\$

Step-by-step explanation:

As the given Augmented matrix is

$\left[\begin{array}{ccccc}9&-2&0&-4&:8\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]$

Step 1 :

$r_{1}$ ↔ $r_{1} - r_{2}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]$

Step 2 :

$r_{3}$ ↔ $r_{3} - 8r_{1}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\0&124&-54&77&:-82\end{array}\right]$

Step 3 :

$r_{2}$ ↔ $\frac{r_{2}}{7}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&124&-54&77&:-82\end{array}\right]$

Step 4 :

$r_{1}$ ↔ $r_{1} + 14r_{2}$ , $r_{3}$ ↔ $r_{3} - 124r_{2}$

$\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&- \frac{254}{7} &\frac{663}{7} &:-\frac{1690}{7} \end{array}\right]$

Step 5 :

$r_{3}$ ↔ $\frac{r_{3}. 7}{254}$

$\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&1&-\frac{663}{254} &:-\frac{1690}{254} \end{array}\right]$

Step 6 :

$r_{1}$ ↔ $r_{1} - 4r_{3}$ , $r_{2}$ ↔ $r_{2} + \frac{1}{7} r_{3}$

$\left[\begin{array}{ccccc}1&0&0&-\frac{71}{127} &:\frac{176}{127} \\0&1&0&-\frac{131}{254} &:\frac{284}{127} \\0&0&1&-\frac{663}{254} &:\frac{845}{127} \end{array}\right]$

∴ we get

$x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\$

6 0

2 years ago

Which of the following systems of linear equations has no solution?

yanalaym [24]

None of the above!!!!!!

8 0

3 years ago

Read 2 more answers

Susan and Steven are cousins. The sum of their ages is 33. The difference between three times Steven's age and half of Susan's a

VARVARA [1.3K]

The complete question is
Susan and Steven are cousins. The sum of their ages is 33. The difference between three times Steven's age and half of Susan's age is 36. Find <span>the age of Susan and Steven

let
x-----> </span>Susan's age
y----> Steven's age

we know that
y+x=33-----> equation 1
3y-x/2=36----> multiply by 2----> 6y-x=72----> equation 2
adds equation 1 and equation 2

y+x=33
6y-x=72
-------------+
7y=105--------> y=15
x=33-y----> x=33-15----> x=18

the answer is
Susan's age is 18
Steven's age is 15

5 0

3 years ago

7x + 2y = 4

Vinil7 [7]

$7x + 2(x + 1) = 4 \\ 7x + 2x + 2 = 4 \\ 9x + 2 = 4 \\ 9x = 2 \\ x = \frac{2}{9} \\ \\ y = \frac{2}{9} + 1 = \frac{11}{9} \\ ( \frac{2}{9} \: \frac{11}{9} )$

5 0

2 years ago

Read 2 more answers