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3 years ago

. 32+4 X (16 X �) -2 pls help

Mathematics

1 answer:

Karo-lina-s [1.5K]3 years ago

3 0

Answer:

Step-by-step explanation:

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A triangle has sides with lengths of 2x - 7, 5x - 3, and 2x - 2. What is the perimeter of the triangle

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4 years ago

jill's fish weighs 8 times as much as her parakeet. together, the pets weigh 63 ounce. how much does the fish weigh?

andriy [413]

1. Jill’s fish weighs 8 times as much as her parakeet.
Together they weigh 63 ounce.
Find the weight of the fish.
=> Jill’s Fish = 8x
=> Parakeet = x
Equation:
=> 8x + x = 63
=> 9x = 63
=> 9x / 9 = 63 / 9
=> 7 ounce
Thus the weight of fish = 8(7)
=> 56 ounce
Which is 8 times as much as parakeet which is 7
=> 56 + 7 = 63 ounce

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4 years ago

The height (feet) of an object moving vertically is given by s= (-16t^2)+(208t)+(156), where t is in seconds.

OverLord2011 [107]

Answer:

The object's velocity at t = 7 is -16 ft/s

The maximum height is 832 ft and it occurs when $t=\frac{13}{2}$

Step-by-step explanation:

From the information given, the equation of motion of the object is

$s(t)= -16t^2+208t+156$

For any equation of motion s(t), the instantaneous velocity at time t is given by

$v(t)=\frac{ds}{dt}$

(a) To find the object's velocity at t = 7, you must:

$v(t)=\frac{d}{dt}(-16t^2+208t+156)\\\\v(t)=-\frac{d}{dt}\left(16t^2\right)+\frac{d}{dt}\left(208t\right)+\frac{d}{dt}\left(156\right)\\\\v(t)=-32t+208+0\\\\v(t)=-32t+208$

Next, we evaluate when t = 7

$v(7)=-32(7)+208=-224+208\\\\v(7)=-16$

The object's velocity at t = 7 is -16 ft/s

(b) To find the maximum of a function we always use the derivative of the function and we set it equal zero to find the critical points.

To find the maximum height and when it occurs, we set the velocity function equal to 0 and solve for t.

$-32t+208=0\\\\-32t+208-208=0-208\\\\-32t=-208\\\\\frac{-32t}{-32}=\frac{-208}{-32}\\\\t=\frac{13}{2}$

Next, we substitute this value into the equation of motion to find the maximum height

$s(\frac{13}{2})= -16(\frac{13}{2})^2+208(\frac{13}{2})+156\\\\s(\frac{13}{2})=-676+1352+156)=832$

The maximum height is 832 ft and it occurs when $t=\frac{13}{2}$

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