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kolezko [41]
3 years ago
10

M is the midpoint of CF (line over it) for the points C(3,4) and F(9,8). Find MF

Mathematics
1 answer:
elena55 [62]3 years ago
3 0
(\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2}) \\(\frac{3 + 9}{2}, \frac{4 + 8}{2}) \\(\frac{12}{2}, \frac{12}{2}) \\(6, 6)

Midpoint of CF: (6, 6)
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Lets set the two numbers as 'a' and 'b'

Now let us set up some equations based on the information:

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Equations

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 a - b = 15 -- equation 2

Solve:

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