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kolezko [41]
3 years ago
10

M is the midpoint of CF (line over it) for the points C(3,4) and F(9,8). Find MF

Mathematics
1 answer:
elena55 [62]3 years ago
3 0
(\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2}) \\(\frac{3 + 9}{2}, \frac{4 + 8}{2}) \\(\frac{12}{2}, \frac{12}{2}) \\(6, 6)

Midpoint of CF: (6, 6)
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Solve the system below using elimination<br> {5x+9y= -10}<br> {7x+10y= -1}
bixtya [17]

∑Hey , jillianwagler ⊃

Answer:

x = 7, y = -5

Step-by-step explanation:

<u><em>Given~:</em></u>

<em>Solve the system below using elimination</em>

<em>{5x+9y= -10}</em>

<em>{7x+10y= -1}</em>

<u><em>Solve:</em></u>

<u><em></em></u>\begin{bmatrix}5x+9y=-10\\ 7x+10y=-1\end{bmatrix}

Isolate x ( 5x + 9y = -10 ) : \mathrm{x=\frac{-10-9y}{5}}

Substitute: \mathrm{x=\frac{-10-9y}{5}}

\begin{bmatrix}7\cdot \frac{-10-9y}{5}+10y=-1\end{bmatrix}

\begin{bmatrix}\frac{-70-13y}{5}=-1\end{bmatrix}

Isolate y : \frac{-70-13y}{5}=1:y=-5

Substitute: y=-5

x=\frac{-10-9\left(-5\right)}{5}=7

Hence, x=7

Therefore, the solution for \begin{bmatrix}5x+9y=-10\\ 7x+10y=-1\end{bmatrix} are:

x=7,\:y=-5

<u><em>xcookiex12</em></u>

<u><em></em></u>

<em>8/19/2022</em>

6 0
2 years ago
Would you use the median or mean to describe the center of each data set? Explain your reasoning. Heights of 50 basketball playe
Ludmilka [50]

Answer:

Median is used to describe the center of the data of heights of 50 basketball players.

Step-by-step explanation:

The median divides the data into two equal parts.

It can be used to describe the center of the data.

The mean gives the average where most data lies.

The advantages of median are

1)it is located even when the values are not capable of quantitative measurements.

2) It is not affected by extreme values > It can be computed even when a frequency distribution  involves open end classes like those of income and prices.

3) In a highly skewed distribution median is appropriate average to use.

The disadvantages of the mean are

1) it is greatly affected by extreme values.

2) It sometimes gives fallacious conclusions.

3) In a highly skewed distribution mean is  not an appropriate average to use.

4) It cannot be computed even when a frequency distribution  involves open end classes like those of income and prices.

4 0
3 years ago
Tim's bean sprout grew 3/ inches. Teegan's bean sprout grew 2 3/4 inches. How many more inches did Tim's bean sprout grow than T
ki77a [65]

Answer:

Tim's bean sprout grow by more than \frac{5}{8} \text{ inches}.

Step-by-step explanation:

We are given that Tim's bean sprout grew 3 3/8 inches. Teegan's bean sprout grew 2 3/4 inches.

We have to find how many more inches did Tim's bean sprout grow than Teegan's.

Firstly, converting both the mixed fractions in improper fraction get;

Tim's bean sprout grew = 3\frac{3}{8} = \frac{27}{8} \text{ inches}

Teegan's bean sprout grew = 2\frac{3}{4} = \frac{11}{4} \text{ inches}

Since the denominator of both the fractions is not the same, so we can't compare them both as which is larger or smaller.

Tim's bean sprout grew = \frac{27\times 1}{8\times 1} = \frac{27}{8} \text{ inches}

Teegan's bean sprout grew = \frac{11 \times 2}{4\times 2}=\frac{22}{8} \text{ inches}

Now, we can clearly see that Tim's bean sprout grew more than Teegan's bean sprout.

So, Tim's bean sprout grow by more than = \frac{27}{8}- \frac{22}{8} = \frac{5}{8} \text{ inches}

Hence, Tim's bean sprout grow by more than \frac{5}{8} \text{ inches}.

8 0
3 years ago
Which statement about the polynomial function g(x) is true?
kakasveta [241]

Answer:

C) If the leading coefficient of g(x) is 1, all rational roots of g(x) = 0 must be integers.

Step-by-step explanation:

6 0
3 years ago
Please help explanation if possible
Vilka [71]

Answer:

Number of years between 1950 and 2100 =

2100 - 1950 = 150 \: years

150 = 50 + 50 + 50 years.

2500000 \times 150 = 375,000,000

So, total population in 2100 is 375,000,000.

8 0
3 years ago
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