3 years ago

M is the midpoint of CF (line over it) for the points C(3,4) and F(9,8). Find MF

1 answer:

3 0

$(\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2}) \\(\frac{3 + 9}{2}, \frac{4 + 8}{2}) \\(\frac{12}{2}, \frac{12}{2}) \\(6, 6)$

Midpoint of CF: (6, 6)

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