Answer:
t_a = 7 s
t_w = 5 s
Step-by-step explanation:
Given:
- The average speed in air v_a = 16 m/s
- The average speed in water v_w = 3 m/s
- The total distance D = 127 m
- The total time T = 12 s
Find:
How long did the stone fall in air and how long did it fall in the water?
Solution:
- Lets time taken by stone to drop through air as t_a = t_a.
- The time taken in water would be t_w = (12 - t_a)
- The total distance covered can be calculated as:
D = v_a*t_a+ v_w*(12 - t_a)
127 = 16*t_a + 3*(12 - t_a)
Simplify and solve for t:
91 = 16*t_a - 3t_a
13*t_a = 91
t_a = 7 s
t_w = 5 s
You multiply the 2 together 4 5/6 and 2 2/3.
4 5/6=29/6
2 2/3=8/3
you multiply the tops together then the bottoms together
29*8=232
3*6=18
232/18=116/9
Answer: 5.66666666667
Step-by-step explanation: Thanks and have a Savage day.
Answer:
Option B. 
.
Step-by-step explanation:
The given equation is kx - 4 = 9
We will add 4 on both the sides of the equation
kx - 4 +4 = 9 +4
kx = 13
Now we will divide by k on both the sides of the equation
Therefore Option B x = 13/k is the right answer.
