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goldenfox [79]
3 years ago
13

What are the solutions to this quadratic equation? 5x2-7x-18=0

Mathematics
2 answers:
klio [65]3 years ago
8 0

open up the image so you can see the answer ! hope it helps you :)

sammy [17]3 years ago
4 0

Answer:

=

−

±

2

−

4

√

2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}

x=2a−b±b2−4ac​​

Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.

5

2

−

7

−

1

8

=

0

5x^{2}-7x-18=0

5x2−7x−18=0

=

5

a={\color{#c92786}{5}}

a=5

=

−

7

b={\color{#e8710a}{-7}}

b=−7

=

−

1

8

c={\color{#129eaf}{-18}}

c=−18

=

−

(

−

7

)

±

(

−

7

)

2

−

4

⋅

5

(

−

1

8

)

Step-by-step explanation:

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( 2 x - 3 ) ( 7 x + 4)
weeeeeb [17]

Answer:5x times -7

Step-by-step explanation:

You ignore the brackets and move the 2x to the other side. Then move the 4 to the other side

3 0
3 years ago
Please help me and If your answer is wrong or not appropreat I will report it
arsen [322]

Answer:

972 x^16 y^24

Step-by-step explanation:

Simplify the following:

(-2 x^3 y^7)^2 (3 x^2 y^2)^5

Multiply each exponent in -2 x^3 y^7 by 2:

(-2)^2 x^(2×3) y^(2×7) (3 x^2 y^2)^5

2×7 = 14:

(-2)^2 x^(2×3) y^14 (3 x^2 y^2)^5

2×3 = 6:

(-2)^2 x^6 y^14 (3 x^2 y^2)^5

(-2)^2 = 4:

4 x^6 y^14 (3 x^2 y^2)^5

Multiply each exponent in 3 x^2 y^2 by 5:

4 x^6 y^14×3^5 x^(5×2) y^(5×2)

5×2 = 10:

4×3^5 x^6 y^14 x^(5×2) y^10

5×2 = 10:

4×3^5 x^6 y^14 x^10 y^10

3^5 = 3×3^4 = 3 (3^2)^2:

4×3 (3^2)^2 x^6 y^14 x^10 y^10

3^2 = 9:

4×3×9^2 x^6 y^14 x^10 y^10

9^2 = 81:

4×3×81 x^6 y^14 x^10 y^10

3×81 = 243:

4×243 x^6 y^14 x^10 y^10

4 x^6 y^14×243 x^10 y^10 = 4 x^(6 + 10) y^(14 + 10)×243:

4×243 x^(6 + 10) y^(14 + 10)

14 + 10 = 24:

4×243 x^(6 + 10) y^24

6 + 10 = 16:

4×243 x^16 y^24

4×243 = 972:

Answer: 972 x^16 y^24

8 0
2 years ago
Read 2 more answers
PLZ HELP I AM FAILING AND NEED HELP!!!!
MA_775_DIABLO [31]

Answer: About 13% of the school would be in chess club.

Step-by-step explanation: Out of 85 students, 11 were in chess club. So:

11 / 85 = 0.1294117647, or approximately 13%.

If it's not too much to ask, may I have brainliest?

5 0
3 years ago
Find the area of a regular hexagon whose apothem is 1.7 cm and side length is 2 cm.. A. 20.4 cm2. B. 3.4 cm2. C. 6.8 cm2. D. 10.
Kipish [7]
A regular hexagon is composed of 6 regular triangles whose area is equal to half of the product of the apothem and side.
                        A - triangle = (1/2)(a)(s) = (1/2)(1.7 cm)(2 cm) = 1.7 cm²
Multiplying this area by 6 to get the area of the hexagon gives as the answer which is 10.2 cm². Therefore, the answer is letter D. 
5 0
2 years ago
How can you solve an equation like this 8x-17 by its self
nalin [4]

Step-by-step explanation:

This is an algebraic expression, not an equation

4 0
3 years ago
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