6)
KM bisects on <NKL so m<MKN = m<MKL = 3x + 5
2(m<MKL) + m<JKN = 180
2(3x+5) + 8x + 2 = 180
6x + 10 + 8x + 2 = 180
14x + 12 = 180
14x = 168
x = 12
so
m<MKN = m<MKL = 3x + 5 = 3(12) + 5 = 36 + 5 = 41
answer
b. 41
7)
2 supplementary has sum = 180
x + x + 14 = 180
2x + 14 = 180
2x = 166
x = 83
x + 14 = 83 + 14 = 97
2 angles are 83 and 97
answer
b. 83, 97
Study all notes, reread the chapters again. Have someone ask questions on the chapters page by page. This always has worked for me. Plus try to do this again the night before the test. You will be surprised how much you can remember by doing it again the night before the test. Hope this helps.
Answer:
Yes, they do
Step-by-step explanation:
Because
6+8=14>9
6+9=15>8
8+9=17>6
Answer:
([-3], [0]), ([3], [0])
Step-by-step explanation:
The given equation of the hyperbola is presented as follows;
The vertices of an hyperbola (of the form) 
are (± a, 0)
The given hyperbola can we presented in a similar form as follows;
Therefore, by comparison, the vertices of the parabola are (± 3, 0), which gives;
The vertices of the parabola are ([-3], [0]), ([3], [0]).
