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s2008m [1.1K]
3 years ago
5

In a popular online role playing game, players can create detailed designs for their character's "costumes," or appearance. Boub

acar sets up a website where players can buy and sell these costumes online. Information about the number of people who visited the website and the number of costumes purchased in a single day is listed below.
120 visitors purchased no costume.
235 visitors purchased exactly one costume.
3 visitors purchased more than one costume.

Based on these results, express the probability that the next person will purchase no costume as a percent to the nearest whole number.
Mathematics
2 answers:
kati45 [8]3 years ago
6 0

Answer:

Step-by-step explanation:

p[p

Tanya [424]3 years ago
4 0

Answer: 34%

Step-by-step explanation:

(Trust me)

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DaniilM [7]

Answer:

Mia is correct.

Step-by-step explanation:

You can see this if you write 5/11 in a calculator, you get 0.454545454545 infinitely. In other cases, you would write it like Malik said if the answer were to be 0.455555555, but it isn't.

6 0
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Which of the following correctly completes the square for the equation
sveticcg [70]
The answer will be B
4 0
3 years ago
I just need no. a please help me to prove this. ​
OleMash [197]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: A + B + C = π    and         cos A = cos B · cos C

scratchwork:

  A + B + C = π

               A = π - (B + C)

         cos A = cos [π - (B + C)]                              Apply cos

                    = - cos (B + C)                                    Simplify

                    = -(cos B · cos C - sin B · sin C)          Sum Identity

                    = sin B · sin C - cos B · cos C               Simplify

cos B · cos C = sin B · sin C - cos B · cos C               Substitution

2cos B · cos C = sin B · sin C                                        Addition

                     2=\dfrac{\sin B\cdot \sin C}{\cos B \cdot \cos C}                                     Division

                     2 = tan B · tan C

\text{Use the Sum Identity:}\quad \tan(B+C)=\dfrac{\tan B+\tan C}{1-\tan B\cdot \tan C}

<u>Proof LHS → RHS</u>

Given:                              A + B + C = π

Subtraction:                     A = π - (B + C)

Apply tan:                  tan A = tan(π - (B + C))

Simplify:                               = - tan (B + C)

\text{Sum Identity:}\qquad \qquad \qquad =-\bigg(\dfrac{\tan B+\tan C}{1-\tan B\cdot \tan C}\bigg)

Substitution:                        = -(tan B + tan C)/(1 - 2)

Simplify:                               = -(tan B + tan C)/-1

                                            = tan B + tan C

LHS = RHS:   tan B + tan C = tan B + tan C  \checkmark

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The answer should be D
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