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Drupady [299]
3 years ago
8

PLEASE HELP ASAP!!! WILL MAKE YOU THE BRAINLYIST!!!!

Mathematics
1 answer:
elena55 [62]3 years ago
3 0
15 ppl would fit

Bc if you find the area of the dance floor which is 20 feet times 30 feet it equals 60 feet. Then multiply how much space someone takes which is 2 feet times 2 feet equals 4 feet. Then you divide the area of the dance floor by the number for F space one person takes up which is 60÷4. You would get 15 people
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Les bought 6 pairs of shorts for s dollars each and a blazer that cost three times as much as the pair of shorts. He spent a tot
cestrela7 [59]
6 pairs of shorts, for a
"s" dollars. A blazer costs 3 times as much, she bought one. The total was 139.50

6s + 3(6s) = 139.50
6s + 18s = 139.50
25s = 139.50 Divide everything by 25,
s = 5.58, which is how much the shorts were. Now for the blazers ;

It said they were three times the cost of shorts, if shorts are 5.58, it is 3*5.58.
3s
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The blazer cost 16.74
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romanna [79]
It would be a right angle
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3 years ago
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nika2105 [10]

Answer:

6 cm = 2.36 in (rounded to the nearest hundred)

Step-by-step explanation:

hope this helps :)

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Y=6x4 + 7x2 and x = vw +1
belka [17]

Answer:

w=-1/6 or w=-3

Step-by-step explanation:

Substitute the value of x and y into the first equation and solve for w:

y=6x^4+7x^2\\10=6(\sqrt{w+1})^4+7(\sqrt{w+1})^2\\10=6(w+1)^2+7(w+1)\\10=6(w^2+2w+1)+7w+7\\10=6w^2+12w+6+7w+7\\0=6w^2+19w+3

Solve for w with the quadratic formula:

w=\frac{-b\±\sqrt{b^2-4ac}}{2a} \\w=\frac{-19\±\sqrt{19^2-4(6)(3)} }{2(6)}\\w=\frac{-19\±\sqrt{361-72}}{12} \\w=\frac{-19\±\sqrt{289} }{12} \\w=\frac{-19\±17}{12}

After simplifying, we get either w=-1/6 or w=-3.

Not sure if w needs to satisfy all conditions while maintaining everything as real numbers, because if w=-3, then x is an imaginary number. But both values work just as fine.

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2 years ago
Under a dilation centered at the origin, the point (-4 , 3) has image at (8 , -6) The dilation is
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Answer:

Balanced chemical equations only show formulae, not names. A balancing number, written in normal script, multiplies all the atoms in the substance next to it.

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