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3 years ago

3/8 + 1/4 = Tap on the pic to see wiestion

Mathematics

2 answers:

Radda [10]3 years ago

6 0

Answer:

3/8 + 1/4 is 5/8 and 1/10+4/5 is 1

Step-by-step explanation:

convert 1/4 to 2/8 and add to 3/8 to get 5/8

convert 4/5 to 9/10 and add to 1/10 equals 10/10 which is also 1

stira [4]3 years ago

5 0

Answer:

9/10 (and 5/8 for question in title)

Step-by-step explanation:

To add fractions, you need to make a common denominator, which you can have a common denominator of 10.

To do this, multiply the numerator (4) and the denominator (5) by 2. You will get 8/10.

Now you can add them together: 8/10 + 1/10 = 9/10

I don't know if you wanted the question in the title answered too so here:

Same thing; common denominator. Use 8. Multiply 1 by 2 and 4 by 2. You get 2/8.

Add: 3/8 + 2/8 = 5/8

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ILL GIVE YOU BRAINLIST !! * have to get it right * Find the slope of the line represented in the table.

cestrela7 [59]

Answer:

2/3 (B)

Step-by-step explanation:

The y values increase by 2 every time and the x values increase by 3. The rule for slope is rise(y)/run(x) so you get b, 2/3

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3 years ago

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evablogger [386]

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3 years ago

Hom many times can the customer drive around the track for $8

wlad13 [49]

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3 years ago

The number of pages in the U.S. tax code exceeds the number of pages in the King James Bible by 18,528. The combined number of p

LenaWriter [7]

Make two equations. Then solve. Let t and b represent the numbers of pages in the Tax Code and Bible, respectively.
t - b = 18,528 . . . . . tax code exceeds Bible by 18,528 pages
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Add the two equations.
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3 years ago

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Tomika heard that the diagonals of a rhombus are perpendicular to each other. Help her test her conjecture. Graph quadrilateral

Stella [2.4K]

Answer:

a. The four sides of the quadrilateral ABCD are equal, therefore, ABCD is a rhombus

b. The equation of the diagonal line AC is y = 5 - x

The equation of the diagonal line BD is y = 5 - x

c. The diagonal lines AC and BD of the quadrilateral ABCD are perpendicular to each other

Step-by-step explanation:

The vertices of the given quadrilateral are;

A(1, 4), B(6, 6), C(4, 1) and D(-1, -1)

a. The length, l, of the sides of the given quadrilateral are given as follows;

$l = \sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}$

The length of side AB, with A = (1, 4) and B = (6, 6) gives;

$l_{AB} = \sqrt{\left (6-4 \right )^{2}+\left (6-1 \right )^{2}} = \sqrt{29}$

The length of side BC, with B = (6, 6) and C = (4, 1) gives;

$l_{BC} = \sqrt{\left (1-6 \right )^{2}+\left (4-6 \right )^{2}} = \sqrt{29}$

The length of side CD, with C = (4, 1) and D = (-1, -1) gives;

$l_{CD} = \sqrt{\left (-1-1 \right )^{2}+\left (-1-4 \right )^{2}} = \sqrt{29}$

The length of side DA, with D = (-1, -1) and A = (1,4) gives;

$l_{DA} = \sqrt{\left (4-(-1) \right )^{2}+\left (1-(-1) \right )^{2}} = \sqrt{29}$

Therefore, each of the lengths of the sides of the quadrilateral ABCD are equal to √(29), and the quadrilateral ABCD is a rhombus

b. The diagonals are AC and BD

The slope, m, of AC is given by the formula for the slope of a straight line as follows;

$Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Therefore;

$Slope, \, m_{AC} =\dfrac{1-4}{4-1} = -1$

The equation of the diagonal AC in point and slope form is given as follows;

y - 4 = -1×(x - 1)

y = -x + 1 + 4

The equation of the diagonal AC is y = 5 - x

$Slope, \, m_{BD} =\dfrac{-1-6}{-1-6} = 1$

The equation of the diagonal BD in point and slope form is given as follows;

y - 6 = 1×(x - 6)

y = x - 6 + 6 = x

The equation of the diagonal BD is y = x

c. Comparing the lines AC and BD with equations, y = 5 - x and y = x, which are straight line equations of the form y = m·x + c, where m = the slope and c = the x intercept, we have;

The slope m for the diagonal AC = -1 and the slope m for the diagonal BD = 1, therefore, the slopes are opposite signs

The point of intersection of the two diagonals is given as follows;

5 - x = x

∴ x = 5/2 = 2.5

y = x = 2.5

The lines intersect at (2.5, 2.5), given that the slopes, m₁ = -1 and m₂ = 1 of the diagonals lines satisfy the condition for perpendicular lines m₁ = -1/m₂, therefore, the diagonals are perpendicular.

5 0

3 years ago