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Alexandra [31]
3 years ago
8

I need this for myself. Help

Mathematics
2 answers:
saw5 [17]3 years ago
5 0

Answer:

Step-by-step explanation:

Ivenika [448]3 years ago
4 0
The answer is b because -2x+1-1<=-35 = -2x<=-36
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According to the Bureau of Labor Statistics, citizens remain unemployed for an average of 15.9 weeks before finding their next j
Ahat [919]

Complete Question

According to the Bureau of Labor Statistics, citizens remain unemployed for an average of 15.9 weeks before finding their next job (June, 2008). Suppose you want to show that Louisiana has been effective in getting their unemployed back to work sooner. You take a random sample of 50 citizens who were unemployed six months earlier and ask them to report the duration. You find that the average time spent unemployed was 13.4 weeks with a sample standard deviation of the time unemployed is 6.7 weeks.

1 Which of the following statements is the correct alternative hypothesis?

2 The test statistic for testing the hypothesis is

a. -2.64

b. -2.32

c. -2.11

d. -1.28

e. none of these are correct

Answer:

1  

 The  alternative hypothesis  H_a  :  \mu < 15.9

2

The  test statistics z =  -2.64  

Step-by-step explanation:

From the question we are told that

     The population  mean value for time  citizens remain unemployed is  \mu  =  15.9 \  weeks

     The  sample size is  n =  50

     The  sample standard deviation is  6.7 weeks.

      The  sample mean value for time  citizens remain unemployed is  \mu  =  15.9 \  weeks

       

     The  null hypothesis is  H_o  :  \mu \ge 15.9

      The  alternative hypothesis  H_a  :  \mu < 15.9

Generally test statistics is mathematically represented as

       z =  \frac{ \= x  - \mu }{ \frac{s}{\sqrt{n} } }  

=>    z =  \frac{13.4 - 15.9}{\frac{6.7}{\sqrt{50}}}

=>     z =  -2.64  

   

7 0
3 years ago
What angle corresponds to angle AFG?
viva [34]

Look at the image below :)

In case you didn't know, corresponding angles are equal to each other and are on the same side of the traversal

Therefore the answer is angle CGH

Hope this helped!  

7 0
3 years ago
Read 2 more answers
Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X &gt; 10) b. P(X &gt; 20) c
GrogVix [38]

Answer:

(a) The value of P (X > 10) is 0.3679.

(b) The value of P (X > 20) is 0.1353.

(c) The value of P (X < 30) is 0.9502.

(d) The value of x is 30.

Step-by-step explanation:

The probability density function of an exponential distribution is:

f(x)=\lambda e^{-\lambda x};\ x>0, \lambda>0

The value of E (X) is 10.

The parameter λ is:

\lambda=\frac{1}{E(X)}=\frac{1}{10}=0.10

(a)

Compute the value of P (X > 10) as follows:

P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353

Thus, the value of P (X > 20) is 0.1353.

(c)

Compute the value of P (X < 30) as follows:

P(X

Thus, the value of P (X < 30) is 0.9502.

(d)

It is given that, P (X < x) = 0.95.

Compute the value of <em>x</em> as follows:

P(X

Take natural log on both sides.

ln(e^{-0.10x})=ln(0.05)\\-0.10x=-2.996\\x=\frac{2.996}{0.10}\\ =29.96\\\approx30

Thus, the value of x is 30.

7 0
3 years ago
Can someone help me? I'll reward points and brainalist
UNO [17]

Answer:

135 degrees

Step-by-step explanation:

45 is for half of the square so u would add 45+45+45 or 45x3. there is a half and 1 whole square.

7 0
3 years ago
Read 2 more answers
Evaluate the function f(x) at the given numbers (correct to six decimal places).
statuscvo [17]

Answer:

The values of given function are shown in the below table.

Step-by-step explanation:

The given function is

f(x)=\frac{x^2-5x}{x^2-x-20}

Simplify the given function.

f(x)=\frac{x(x-5)}{x^2-5x+4x-20}

f(x)=\frac{x(x-5)}{x(x-5)+4(x-5)}

f(x)=\frac{x(x-5)}{(x+4)(x-5)}

Cancel out the common factor.

f(x)=\frac{x}{x+4}

Substitute x=5.5 in the above equation.

f(5.5)=\frac{5.5}{5.5+4}

f(5.5)=\frac{5.5}{9.5}

f(5.5)=0.57894736842

f(5.5)\approx 0.578947

Similarly find the value for all values of x.

The values of given function are shown in the below table.

8 0
3 years ago
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