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2 years ago

Help pls! (4c+4)(2c-3)

Mathematics

2 answers:

VMariaS [17]2 years ago

5 0

Answer:

8c2 - 4c - 12

Step-by-step explanation:

vredina [299]2 years ago

5 0

Answer:

8c^2-4c-12

Step-by-step explanation

So you have to multiply 4c into 2c and -3 first and then 4 into 2c and -3.

(4c+4)(2c-3)

4c X 2c is 8c^2

(4c+4)(2c-3)

4c X -3 is -12c

So for the 4c multiplying in you would get 8c^2 and -12c, but we still have to multiply in the 4

4 X 2c is 8c

(4c+4)(2c-3)

4 X -3 is -12

So then we would get 8c^2-12c+8c-12, however we can still combine the -12c and the 8c. Combining those would get -4c. So the final answer is 8c^2-4c-12

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stealth61 [152]

Answer:

3/25

Step-by-step explanation:

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3 years ago

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kap26 [50]

Parallel=same slope
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3 years ago

A company sells widgets. The amount of profit, y, made by the company, is related to the selling price of each widget, x, by the

7nadin3 [17]

Answer:

Widgets should be sold by $38.88 to maximize the profit.

Step-by-step explanation:

Vertex of a quadratic function:

Suppose we have a quadratic function in the following format:

$f(x) = ax^{2} + bx + c$

It's vertex is the point $(x_{v}, y_{v})$

In which

$x_{v} = -\frac{b}{2a}$

$y_{v} = -\frac{\Delta}{4a}$

Where

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In this question:

The profit is given by:

$y = -9x^2 + 700x - 6005$

Which is a quadratic function with $a = -9, b = 700, c = -6005$

The maximum profit happens at the x of the vertex. Thus

$x_{v} = -\frac{b}{2a} = -\frac{700}{2(-9)} = 38.88$

Widgets should be sold by $38.88 to maximize the profit.

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2 years ago

Health insurers are beginning to offer telemedicine services online that replace the common office visit. A company provides a v

Veronika [31]

Answer:

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Step-by-step explanation:

Let us find out the mean savings for a televisit to the doctor from the given data.

Using Excel,

=AVERAGE(number1, number2,....)

The mean is found to be

$\bar{x} = \$71$

Let us find out the standard deviation of savings for a televisit to the doctor from the given data.

Using Excel,

=STDEV(number1, number2,....)

The standard deviation is found to be

$s = \$ 22.35$

The confidence interval is given by

$\text {confidence interval} = \bar{x} \pm MoE\\\\$

Where the margin of error is given by

$$ MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) $ \\\\$

Where n is the sample of 20 online doctor visits, s is the sample standard deviation and $t_{\alpha/2}$ is the t-score corresponding to a 95% confidence level.