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Degger [83]
3 years ago
10

The length, width and height of a rectangular prism is given as 15 cm, 10

Mathematics
2 answers:
aliina [53]3 years ago
7 0

Answer:

Its option C

Step-by-step explanation:

to find the volume you multiply the length, width and height together.

Degger [83]3 years ago
5 0
C is the correct answer.

Why?

Volume is calculated by multiplying a, b and c
V = a x b x c
V= 15 cm x 10 cm x 5 cm
V= 750cm^3

Do note that since we are finding the volume, the proper measurement would be cm^3
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Four ninths plus nine eighteenths :]
goldenfox [79]

Answer:  17/18

In words, this is seventeen eighteenths

==========================================

Work Shown:

4/9 + 9/18

8/18 + 9/18 ... see note below

(8+9)/18

17/18

----------------

note: To go from 4/9 to 8/18, we multiply top and bottom by 2. So that's why 4/9 = 8/18.

The diagram below shows a visual representation of why 4/9 = 8/18.

In the top row, I've drawn out 9 rectangles of the same size. Then I've shaded 4 of the 9 rectangles to represent the fraction 4/9. In the bottom row, I've cut each of those 9 rectangles into two smaller equal pieces, so we have 9*2 = 18 rectangles now. Note how the shaded regions are the same size, so this shows 4 green regions doubles to 2*4 = 8 yellow regions; therefore 4/9 is the same as 8/18.

8 0
3 years ago
Is it proportional?Please help me
kvv77 [185]

I believe yes

Each time it goes up by one, it is always increasing by the same amount each time

6 0
3 years ago
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If f(x)=x^2-7 and h(x)=7x-5, then f(h(2))=
zaharov [31]
We are given 3 equations. Using these equations we can find f(h(2)).

h(x)=7x-5
h(2)=7(2)-5
h(2)=14-5
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f(x)=x^2-7
f(h(2))=(7x-5)^2-7
we know the answer for h(2) by now, so we can substitute for that.
f(9)=9^2-7
f(9)=81-7
f(9)=74

so f(h(2))=74
5 0
3 years ago
Use the multiplication property of exponents to determine if each statement is true or false.
lisabon 2012 [21]
1)
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4)
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7 0
3 years ago
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ICE Princess25 [194]
The most exact answer would be 0.19951% but the approximate answer would be 0.2%.
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