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Harrizon [31]
2 years ago
13

Given to

Mathematics
1 answer:
zheka24 [161]2 years ago
7 0

Answer:

Step-by-step explanation:

Given:

\frac{AD}{DC}=\frac{BE}{EC}

To Prove:

AB║DE

Solution:

Since, corresponding sides of ΔACB and ΔDCE are proportional,

\frac{AD}{DC}=\frac{BE}{EC}

Both the triangles will be similar.

ΔACB ~ ΔDCE [By SAS property of similarity]

Therefore, ∠1 ≅ 2 [CPCTC]

Since, ∠1 and ∠2 are the corresponding angles

Therefore, AB║DE [Converse of corresponding angles theorem]

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What is the constant rate of change in given equation Y= -5x *please Hurry*
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121 as a fration simplifid
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What are the real roots of 2x^3-42x-40
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3 years ago
The number of stamps that Kaye and Alberto had were in the ration of 5:3 respecctively. After Kaye gave Alberto 10 of her stamps
masha68 [24]

Answer:  The correct option is

(D) 60.

Step-by-step explanation:  Given that the number of stamps that Kaye and Alberto had were in the ration of 5:3 respectively.

After Kaye gave Alberto 10 of her stamps, the ration of the number of Kaye had to the number of Alberto had was 7:5.

We are to find the number of stamps that Kaye had more than Alberto.

Let the number of stamps Kaye and Alberto has are 5x and 3x respectively.

Then, according to the given information, we have

(5x-10):(3x+10)=7:5\\\\\Rightarrow \dfrac{5x-10}{3x+10}=\dfrac{7}{5}\\\\\Rightarrow 25x-50=21x+70\\\\\Rightarrow4x=120\\\\\Rightarrow x=\dfrac{120}{4}\\\\\Rightarrow x=30.

So, the number of stamps that Kaye had = 5 × 30 = 150

and

the number of stamps that Alberto had = 3 × 30 = 90.

Therefore, the number of stamps that Kaye had more than Alberto is

150-90=60.

Thus, Kaye had 60 stamps more than Alberto.

Option (D) is CORRECT.

7 0
3 years ago
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