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zlopas [31]
3 years ago
11

The students in Mrs. Smith's class placed 26 math textbooks on a scale. The scale indicated a weight of 1,248 ounces. Each math

textbook weighed the same amount. Which shows the weight of 1 math textbook?
Mathematics
1 answer:
irina [24]3 years ago
5 0

Answer:

48 ounces

Step-by-step explanation:

1,248 divided by 26 is 48

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Jake is solving x^2-6x+5=0 by completing the square his steps are shown below step 1. x^2-6x=-5 step 2. x^-6x+9=-5+9 step 3. (x-
damaskus [11]

Answer:

Jake's error in step 3

Step-by-step explanation:

we have

x^{2} -6x+5=0

Complete the square

step 1

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2} -6x=-5

step 2

Complete the square. Remember to balance the equation by adding the same constants to each side

x^{2} -6x+9=-5+9

x^{2} -6x+9=4

step 3

Rewrite as perfect squares

(x-3)^{2}=4

Jake's error in step 3

He placed 6 instead of 3 in the left side

step 4

take square root both sides

\sqrt{(x-3)^2} =\sqrt{4}

step 5

(x-3)=\pm2

step 6

x=3\pm2

step 7

x=5 and x=1

7 0
4 years ago
What is the length of a missing side of a 48 feet and 52 feet 90° triangle
RideAnS [48]

Answer:

5

Step-by-step explanation:

5 0
3 years ago
Find the area of each regular polygon. Round your answer to the nearest tenth if necessary.
tatuchka [14]

*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*

(21)

Area of a Regular Hexagon: \frac{3\sqrt{3}}{2}(side)^{2} = \frac{3\sqrt{3}}{2}*(\frac{20\sqrt{3} }{3} )^{2} =200\sqrt{3} square units

(22)

Similar to (21)

Area = 216\sqrt{3} square units

(23)

For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:

altitude=\frac{\sqrt{3}}{2}*side

side = \frac{36}{\sqrt{3}}

Hence, area of the hexagon will be: 648\sqrt{3} square units

(24)

Given is the inradius of an equilateral triangle.

Inradius = \frac{\sqrt{3}}{6}*side

Substituting the value of inradius and calculating the length of the side of the equilateral triangle:

Side = 16 units

Area of equilateral triangle = \frac{\sqrt{3}}{4}*(side)^{2} = \frac{\sqrt{3}}{4}*256 = 64\sqrt{3} square units

4 0
3 years ago
In one of its Spring catalogs, L.L. Bean® advertised footwear on 28 of its 192 catalog pages. Suppose we randomly survey 20 page
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100 easy os it correct
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