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3 years ago

What is the volume of the shape above??

Mathematics

1 answer:

zimovet [89]3 years ago

4 0

Answer:

720*5=3600

Step-by-step explanation:

8 times 9 times 10 times 5 will give 3600

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You are given the following sequence:

borishaifa [10]

<h2> Question No 1</h2>

Answer:

7.5 is the 4th term of the sequence $60, 30, 15, 7.5, ...$ .

In other words: $\boxed{a_4=7.5}$

Step-by-step explanation:

Considering the sequence

$60, 30, 15, 7.5, ...$

As we know that a sequence is said to be a list of numbers or objects in a special order.

$60, 30, 15, 7.5, ...$

is a sequence starting at 60 and decreasing by half each time. Here, 60 is the first term, 30 is the second term, 15 is the 3rd term and 7.5 is the fourth term.

In other words,

$a_1=60$ ,

$\:a_2=30$ ,

$a_3=15$ , and

$a_4=7.5$

Therefore, 7.5 is the 4th term of the sequence $60, 30, 15, 7.5, ...$ .

In other words: $\boxed{a_4=7.5}$

<h2> Question # 2</h2>

Answer:

The value of a subscript 5 is 16.

i.e. When n = 5, then h(5) = 16

Step-by-step explanation:

To determine:

What is the value of a subscript 5?

Information fetching and Solution Steps:

Chart with two rows.

The first row is labeled n.

The second row is labeled h of n. i.e. h(n)

The first row contains the numbers three, four, five, and six.

The second row contains the numbers four, nine, sixteen, and twenty-five.

Making the data chart

n 3 4 5 6

h(n) 4 9 16 25

As we can reference a specific term in the sequence by using the subscript. From the table, it is clear that 'n' row represents the input and and 'h(n)' represents the output.

So, when n = 5, the value of subscript 5 corresponds with 16. In other words: When n = 5, then h(5) = 16

Therefore, the value of a subscript 5 is 16.

<h2> Question # 3</h2>

Answer:

We determine that the sequence 33, 31, 28, 24, 19, … is neither arithmetic nor geometric.

Step-by-step explanation:

Considering the sequence

33, 31, 28, 24, 19, …

Lets calculate the common difference 'd' to determine if the sequence is Arithmetic or not.

$\mathrm{Compute\:the\:differences\:of\:all\:the\:adjacent\:terms}:\quad \:d=a_{n+1}-a_n$

$d = 31 - 33 = -2$

$d = 28 - 31 = -3$

$d = 24 - 28 = -4$

$d = 19 - 24 = -5$

As the common difference 'd' is not constant. It means the sequence is not Arithmetic.

Lets now calculate the common ratio 'r' to determine if the sequence is Geometric or not.

$\mathrm{Compute\:the\:ratios\:of\:all\:the\:adjacent\:terms}:\quad \:r=\frac{a_n}{a_{n-1}}$

$\frac{31}{33}=0.93939\dots ,\:\quad \frac{28}{31}=0.90322\dots ,\:\quad \frac{24}{28}=0.85714\dots ,\:\quad \frac{19}{24}=0.79166\dots$

The ratio is not constant. It means the sequence is not Geometric.

From the above analysis, we determine that the sequence 33, 31, 28, 24, 19, … is neither arithmetic nor geometric.

<h2> Question # 4</h2>

Answer:

We determine that the sequence -99, -96, -92, -87, -81... is neither arithmetic nor geometric.

Step-by-step explanation:

From the description statement:

''negative 99 comma negative 96 comma negative 92 comma negative 87 comma negative 81 comma dot dot dot''.

The statement can be translated algebraically as

-99, -96, -92, -87, -81...

Lets calculate the common difference 'd' to determine if the sequence is Arithmetic or not.

$\mathrm{Compute\:the\:differences\:of\:all\:the\:adjacent\:terms}:\quad \:d=a_{n+1}-a_n$

$-96-\left(-99\right)=3,\:\quad \:-92-\left(-96\right)=4,\:\quad \:-87-\left(-92\right)=5,\:\quad \:-81-\left(-87\right)=6$

As the common difference 'd' is not constant. It means the sequence is not Arithmetic.

Lets now calculate the common ratio 'r' to determine if the sequence is Geometric or not.

$\mathrm{Compute\:the\:ratios\:of\:all\:the\:adjacent\:terms}:\quad \:r=\frac{a_n}{a_{n-1}}$

$\frac{-96}{-99}=0.96969\dots ,\:\quad \frac{-92}{-96}=0.95833\dots ,\:\quad \frac{-87}{-92}=0.94565\dots ,\:\quad \frac{-81}{-87}=0.93103\dots$

The ratio is not constant. It means the sequence is not Geometric.

From the above analysis, we determine that the sequence -99, -96, -92, -87, -81... is neither arithmetic nor geometric.

<h2> Question # 5</h2>

Step-by-step explanation:

Considering the sequence

12, 22, 30, 36, 41, …

$\mathrm{Compute\:the\:differences\:of\:all\:the\:adjacent\:terms}:\quad \:d=a_{n+1}-a_n$

$22-12=10,\:\quad \:30-22=8,\:\quad \:36-30=6,\:\quad \:41-36=5$

As the common difference 'd' is not constant. It means the sequence is not Arithmetic.

$\mathrm{Compute\:the\:ratios\:of\:all\:the\:adjacent\:terms}:\quad \:r=\frac{a_n}{a_{n-1}}$

$\frac{22}{12}=1.83333\dots ,\:\quad \frac{30}{22}=1.36363\dots ,\:\quad \frac{36}{30}=1.2,\:\quad \frac{41}{36}=1.13888\dots$

The ratio is not constant. It means the sequence is not Geometric.

From the above analysis, we determine that the sequence 12, 22, 30, 36, 41, … is neither arithmetic nor geometric.

8 0

3 years ago

A rectangle has a perimeter of 108 units. The length of the rectangle is 2x+8 units and the width is 3x -4 units. Find the value

Dmitry [639]

The answer should be x=20

8 0

3 years ago

at franks work he can produce 4 widgets every hour which of the following expresses how many widgets frank can make during a who

Arlecino [84]

Wouldn’t frank be able to make 32 widgets in 8 hours

6 0

3 years ago

16. How many liters of a 60% alcohol solution must be added to 60 liters of a 30% alcohol

Nezavi [6.7K]

Step-by-step explanation:

Step 1: Question statement and Inferences

Let x liters of the 60% solution be added.

So, amount of Alcohol in this solution = 60% of x = 0.6x L

Now, let us consider the 40% solution.

The total volume of this solution is 50 L

So, amount of Alcohol in this solution = 40% of 50

Step 2: Finding required values

When x L of 60% solution are mixed with 50 L of the 40% solution, the total volume of the resultant solution will be (50+x) L

By the Law of Conservation of Mass,

Amount of alcohol in the input solutions = Amount of alcohol in the final solution

=> Amount of alcohol in the final solution = 20 + 0.6x

So, concentration of Alcohol in the final solution

Step 3: Calculating the final answer

It is given that the concentration of alcohol in the final solution is 50%

8 0

3 years ago

Read 2 more answers

Find the range of F<img src="https://tex.z-dn.net/?f=f%28x%29%3D%20%5Cfrac%7B2%7D%7Bx-7%7D%20" id="TexFormula1" title="f(x)= \fr

steposvetlana [31]

Answer: $y \in R; y \neq 0$
Explanation: For this, it is often best to find the horizontal asymptote, and then take limits as x approaches the vertical asymptote and the end behaviours.

Well, we know there will be a horizontal asymptote at y = 0, because as x approaches infinite and negative infinite, the graph will shrink down closer and closer to 0, but never touch it. We call this a horizontal asymptote.
So we know that there is a restriction on the y-axis.

Now, since we know the end behaviours, let's find the asymptotic behaviours.

As x approaches the asymptote of 7⁻, then y would be diverging out to negative infinite.
As x approaches the asymptote at 7⁺, then y would be diverging out to negative infinite.

So, our range would be: $y \in R; y \neq 0$

6 0

3 years ago

What is the volume of the shape above??​

What is the volume of the shape above??