Answer:
probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3
Step-by-step explanation:
First of all;
Let B1 be the event that the card with two red sides is selected
Let B2 be the event that the
card with two black sides is selected
Let B3 be the event that the card with one red side and one black side is
selected
Let A be the event that the upper side of the selected card (when put down on the ground)
is red.
Now, from the question;
P(B3) = ⅓
P(A|B3) = ½
P(B1) = ⅓
P(A|B1) = 1
P(B2) = ⅓
P(A|B2)) = 0
(P(B3) = ⅓
P(A|B3) = ½
Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;
P(B3|A) = [P(B3)•P(A|B3)]/[(P(B1)•P(A|B1)) + (P(B2)•P(A|B2)) + (P(B3)•P(A|B3))]
Thus;
P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]
P(B3|A) = (1/6)/(⅓ + 0 + 1/6)
P(B3|A) = (1/6)/(1/2)
P(B3|A) = 1/3
50 I think. 2 1/2 times 20 minutes equals 50
Answer:
On Saturday, a local hamburger shop sold a combined total of 312 hamburgers and cheeseburgers. The number of cheeseburgers sold was three times the number of hamburgers sold, How many hamburgers were sold on Saturday?
Step-by-step explanation:
x is the hamburgers
x times 3 is the cheeseburgers
answer x=78
check work 78 x 3 =234
78 + 234 = 312
WHAT DOES THIS MEAN???... i needa think abt this one
A B C D E represent the subjects
A+A1
A+B2
A+C3
A+D4
A+E5
B+B6
B+C7
B+D8
B+E9
C+C10
C+D11
C+E12
D+D13
D+E14
E+E15
15 combos