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IgorLugansk [536]
3 years ago
8

Helppppppppppppppppppppppppppp

Mathematics
1 answer:
natita [175]3 years ago
8 0

Answer:

1. 302.1 ÷ 5 can be rewritten as 181.26 ÷ 3

2. 12.15 ÷ 0.02 can be rewritten as 2430 ÷ 4

3. 1.375 ÷ 0.11 can be rewritten as 75 ÷ 6

Step-by-step explanation:

Hope this helps!

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Answer:

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28 is our common denominator here.

Step-by-step explanation:

We want to add the fractions   2/7 and 1/4

(2/7) * (4/4)   and    (1/4) * (7/7)

(2/7) * (4/4)   +   (1/4) * (7/7) =  8/28  + 7/28 = 15/28

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 The distance between city A and B is 600 km. The first train left A and headed towards B at the speed of 60 km/hour. The secon
hoa [83]
\bf \begin{array}{ccccllll}
&distance&rate(km/hr)&time(hrs)\\
&\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\\
A&d&60&t\\
B&600-d&v&t+3
\end{array}

\bf \textit{meaning}\implies 
\begin{cases}
d=(60)(t)
\\ \quad \\
600-d=(v)(t+3)\\
------------\\
d=\boxed{60t}\qquad thus
\\ \quad \\
600-\boxed{60t}=v(t+3)\leftarrow \textit{solve for "t"}
\end{cases}

keep in mind, that "t" is the time when the train at A station, left towards B station

they met, at some time "t", and by the time that happened, train from A
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PLEASEEEE HELPPPPPP!!!
artcher [175]

Answer:

18

Step-by-step explanation:

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