All categories

3 years ago

Find the area of a triangular garden if the sides are approximately 6 feet, 14 feet, and 13 feet (to the nearest square foot).

Mathematics

1 answer:

pashok25 [27]3 years ago

5 0

Answer is 39 ft square
A=h•b/2
A=13•6/2
A=78/2
A=39 ft square

I attached photo

You might be interested in

Help with my math please!!!

madam [21]

Answer:

x-12≤7

x≤19

Step-by-step explanation:

less than means it comes after

x-12

is at most means less than or equal to

x-12≤7

Add 12 to each side

x-12+12≤7+12

x≤19

7 0

3 years ago

Read 2 more answers

sineoko [7]

I did not understand Q3 and I could not, but I understood Q2

The answer is Q2: 12 liters

3 0

3 years ago

HELP I’ll make u brainlist

galina1969 [7]

Answer:

-4

Step-by-step explanation:

given

f(x) = 4x - 12

if x = 2,

f(2) = 4(2) - 12

= 8 - 12

= -4

7 0

4 years ago

Read 2 more answers

Multiply 3 by the number of apples in each bag x and add it to 3 times the number of bananas in each bunch y an then multiply th

KIM [24]

Answer:

9(x+y)

(3x + 3y) 3

4 0

3 years ago

g Gravel is being dumped from a conveyor belt at a rate of 10 ft3/min, and its coarseness is such that it forms a pile in the sh

Maslowich

Answer:

0.3537 feet per minute.

Step-by-step explanation:

Gravel is being dumped from a conveyor belt at a rate of 10 ft3/min. Since we are told that the shape formed is a cone, the rate of change of the volume of the cone.

$\dfrac{dV}{dt}=10$ ft^3/min$

$\text{Volume of a cone}=\dfrac{1}{3}\pi r^2 h$

If the Base Diameter = Height of the Cone

The radius of the Cone = h/2

Therefore,

$\text{Volume of the cone}=\dfrac{\pi h}{3} (\dfrac{h}{2}) ^2 \\V=\dfrac{\pi h^3}{12}$

$\text{Rate of Change of the Volume}, \dfrac{dV}{dt}=\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}$

Therefore: $\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}=10$

We want to determine how fast is the height of the pile is increasing when the pile is 6 feet high.

$When h=6$ feet$\\\dfrac{3\pi *6^2}{12}\dfrac{dh}{dt}=10\\9\pi \dfrac{dh}{dt}=10\\ \dfrac{dh}{dt}= \dfrac{10}{9\pi}\\ \dfrac{dh}{dt}=0.3537$ feet per minute$

When the pile is 6 feet high, the height of the pile is increasing at a rate of 0.3537 feet per minute.

7 0

4 years ago