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3 years ago

14

What is the angle measurement of the angle EFGHelpp!!

1 answer:

RoseWind [281]3 years ago

4 0

Answer:

∠EFG = 151°

Step-by-step explanation:

∠EFG = 44° + 107° = 151°

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O<br> Find the values of x and y.<br> 480<br> (5x – 17)<br> 6<br> 2<br> and y<br> (<br> o

ANTONII [103]

Answer:4

Step-by-step explanation: trust me it’s correct

6 0

3 years ago

What is the difference between the temperatures at 10 a.m. and 3:30 p.m.? Indicate whether the change is an increase or decrease

dsp73

Answer:

Change in temperature = - 3.3 F

The temperature has decreased

Step-by-step explanation:

The complete question is attached below .

As given in the attached image

Temperature at 10 A.M $= 1.2$ degree Fahrenheit

Temperature at 3:30 P.M. $= -2.1$ degree Fahrenheit

Change in temperature

= Temperature at 3:30 p.m - Temperature at 10 a.m

= $- 2.1 - 1.2$

$= - 3.3$ F

The temperature has decreased

7 0

3 years ago

sin alpha = 7/25, alpha lies in quadrant ii, and cos beta = 2/5, beta lies in quadrant i. find cos(alpha-beta).

Ilia_Sergeevich [38]

Answer:

Therefore $\cos(\alpha-\beta)=\frac{48+7\sqrt{25}}{125}$

Step-by-step explanation:

Given values are

$\sin \alpha=\frac{7}{25}$

$\cos \beta=\frac{2}{5}$

$\sin^2x+\cos^2=1$

$\cos \alpha=\sqrt{1-\sin^2\alpha}$

$\cos \alpha=\sqrt{1-(\frac{7}{25})^2}$

$\cos \alpha=\sqrt{1-\frac{49}{625}}$

$\cos \alpha=\sqrt{\frac{576}{625}}$

$\cos \alpha=\frac{24}{25}$

$\sin \beta=\sqrt{1-\cos^2\beta}$

$\sin \beta=\sqrt{1-(\frac{2}{5})^2}$

$\sin \beta=\sqrt{1-\frac{4}{25}}$

$\sin \beta=\frac{\sqrt{21}}{5}$

$\cos(\alpha-\beta)=\cos\alpha\cos\beta+\sin\alpha\sin\beta$

$\cos(\alpha-\beta)=\frac{24}{25}\times\frac{2}{5}+\frac{7}{25}\times\frac{\sqrt{21}}{5}$

$\cos(\alpha-\beta)=\frac{48+7\sqrt{25}}{125}$

7 0

3 years ago

Q(x)= 1/2x - 3; q(x) =-4. Find the value of x

Lelu [443]

Answer:

$q(x) =-5$

Step-by-step explanation:

I am solving this using Function Notation.

We are given:

$q(x)= \frac{1}{2}x - 3$

While we are to find:

$q(x) =-4$

In Function Notation, replace all the " $x$ " you see with the value you are given.

So, in this case,

$q(x)= \frac{1}{2}x - 3\\\\=\frac{1}{2}x - 3$

Would become

$q(x)= \frac{1}{2}x - 3\\\\=\frac{1}{2}(-4) - 3$

Now we can solve.

$\frac{1}{2}(-4) - 3$

Use PEMDAS; Parenthesis first;

$\frac{1}{2}(-\frac{4}{1})$

Cross divide: 1 cancels 1, -4 ÷ 2 = -2

Hence, we are left with

$(-2) - 3$

$-5$

Therefore, the value of x is -5

8 0

2 years ago

Three years ago, Sherman was twice as old as Clive. If Clive’s present age is c, which expression represents Sherman’s present a

iogann1982 [59]

2(c-3)=s

because you have to subtract 3 years from sherman's age first, so you need the parentheses

7 0

3 years ago