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ELEN [110]
3 years ago
15

A library labels each book with a six-character code to identify the book in its computer system. The first character is either

a letter or digit, and this is followed by three digits, then two letters. How many different codes are possible
Mathematics
1 answer:
mote1985 [20]3 years ago
4 0

Answer: There are 24336000 different codes that are possible.

Step-by-step explanation:

We know that,

Total alphabets = 26

Total digits = 10

Choices for First place = 26+10=36

Choices for next 3 places = 10 x 10 x 10 = 1000

Choices for last 2 places = 26 x 26 = 676

Total different codes are possible = 36 x 1000 x 676

=24336000

Hence, there are 24336000 different codes that are possible.

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4 years ago
The heights of baby giraffe are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. If 100 b
ANEK [815]

Answer:

P(\bar X

And we can solve this using the following z score formula:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we use this formula we got:

z = \frac{63-63.6}{\frac{2.5}{\sqrt{100}}}= -2.4

So we can find this probability equivalently like this:

P( Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

X \sim N(63.6,2.5)  

Where \mu=63.6 and \sigma=2.5

We select n =100. Since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

We want this probability:

P(\bar X

And we can solve this using the following z score formula:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we use this formula we got:

z = \frac{63-63.6}{\frac{2.5}{\sqrt{100}}}= -2.4

So we can find this probability equivalently like this:

P( Z

4 0
4 years ago
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