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klio [65]
3 years ago
15

What is the x in 4x+20?

Mathematics
2 answers:
Galina-37 [17]3 years ago
5 0

Answer:

the answer is 5 because if you divide it its your answer

vovikov84 [41]3 years ago
3 0

Answer:

x=-5

Step-by-step explanation:

Set " 4x+20" equal to 0 (4x+20=0)

Do the opposite operation of 20 (in this case is subtraction) and subtract 20 from both sides (4x+20-20=0-20).

You'll be left with 4x=-20.

Divide both sides by 4 (4x/4=-20/4).

4 divided 4 equals x.

-20 divided by 4 equals -5.

x=-5.

Hope this was helpful.

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zhuklara [117]
4.579 is the smallest number including decimals
without it would just be 4,579
4 0
3 years ago
) a circle with radius 63mm
Jet001 [13]

Answer:

<em>radius: r2 = 3.14 × 632 = 12470 square mm</em>

Step-by-step explanation:

5 0
3 years ago
The tensile strength of stainless steel produced by a plant has been stable for a long time with a mean of 72 kg/mm2 and a stand
Elanso [62]

Answer:

95% confidence interval for the mean of tensile strength after the machine was adjusted is [73.68 kg/mm2 , 74.88 kg/mm2].

Yes, this data suggest that the tensile strength was changed after the adjustment.

Step-by-step explanation:

We are given that the tensile strength of stainless steel produced by a plant has been stable for a long time with a mean of 72 kg/mm 2 and a standard deviation of 2.15.

A machine was recently adjusted and a sample of 50 items were taken to determine if the mean tensile strength has changed. The mean of this sample is 74.28. Assume that the standard deviation did not change because of the adjustment to the machine.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

                         P.Q. = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean strength of 50 items = 74.28

            \sigma = population standard deviation = 2.15

            n = sample of items = 50

            \mu = population mean tensile strength after machine was adjusted

<em>Here for constructing 95% confidence interval we have used One-sample z test statistics as we know about population standard deviation.</em>

So, 95% confidence interval for the population mean, \mu is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level of

                                                  significance are -1.96 & 1.96}  

P(-1.96 < \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < 1.96) = 0.95

P( -1.96 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X-\mu} < 1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

P( \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

<u><em>95% confidence interval for</em></u> \mu = [ \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ]

                 = [ 74.28-1.96 \times {\frac{2.15}{\sqrt{50} } } , 74.28+1.96 \times {\frac{2.15}{\sqrt{50} } } ]

                 = [73.68 kg/mm2 , 74.88 kg/mm2]

Therefore, 95% confidence interval for the mean of tensile strength after the machine was adjusted is [73.68 kg/mm2 , 74.88 kg/mm2].

<em>Yes, this data suggest that the tensile strength was changed after the adjustment as earlier the mean tensile strength was 72 kg/mm2 and now the mean strength lies between 73.68 kg/mm2 and 74.88 kg/mm2 after adjustment.</em>

8 0
3 years ago
Density of 222.50 g and 25.00 cm3
e-lub [12.9K]

Answer:

8.9 grams per centimeters cubed

Step-by-step explanation:

The formula for density is D=M÷V

Just divide 222.50 by 25.00 and you are done.

8 0
3 years ago
A bag contains 11 tiles, one for each of the letters in the word BLUEBERRIES. You randomly choose a tile.
wel
2/11

there’s 2 R’s and 11 total so

possible outcomes/ overall outcomes
7 0
3 years ago
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