HELPPP!!! question 2,3,4

Mathematics

2 answers:

nordsb [41]3 years ago

7 0

2: The Answer Is D

100 x 11 = 1100

13 x 11 = 143

3: The Answer Is B

500 x 6 = 3000

154 x 6 = 924

Ivan3 years ago

4 0

Answer:

Answer 1: 85

Answer 2: c

Answer 3: 15

Step-by-step explanation:

Simple subtraction makes the trick.

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Colt1911 [192]

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3 years ago

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Without calculating, would 0.4 + (2 + 0.6) be less than, greater than, or equal to 3? Explain.

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3 years ago

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Suppose that an airline overbooks seats on their flights. In particular, it sells 300 tickets for a flight when there are only 2

vladimir1956 [14]

Using the normal approximation to the binomial, it is found that there is a 0.994 = 99.4% probability that we will have enough seats for everyone who shows up.

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.
After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
The binomial distribution is the probability of x successes on n trials, with p probability of a success on each trial. It can be approximated to the normal distribution with $\mu = np, \sigma = \sqrt{np(1-p)}$ .

In this problem:

15% do not show up, so 100 - 15 = 85% show up, which means that $p = 0.85$ .
300 tickets are sold, hence $n = 300$ .

The mean and the standard deviation are given by:

$\mu = np = 300(0.85) = 255$

$\sigma = \sqrt{np(1-p)} = \sqrt{300(0.85)(0.15)} = 6.185$

The probability that we will have enough seats for everyone who shows up is the probability of at most 270 people showing up, which, using continuity correction, is $P(X \leq 270 + 0.5) = P(X \leq 270.5)$ , which is the p-value of Z when X = 270.5.