3(2x+8)=8x+46
6x+24=8x+46
-2x+24=46
-2x=22
x=-11
3(2(-11)+8)=8(-11)+46
3(-22+8)=-88+46
3(-14)=-42
-42=-42
Hope I didn't mess up for your sake
To the left or the right bro?
Unit cost of a ticket = Income from ticket sales / number of tickets sold:
$1250
--------------- = $6.58 per ticket
190 tickets
Again:
$1175
--------------- = $6.71
175 tickets
While ticket prices do change (usually increase) from year to year, it's unusual to see such a situation here.
Don't have any guidelines by which to determine the "fixed cost of a ticket".
If we use the cost of a ticket of 2 years ago ($6.58/ticket), then the income from the sale of 225 tickets this year would be ($6.58/ticket)(225 tickets), or $1480.50.
Answer:
100 ft
Step-by-step explanation:
We need to find the diagonal ( or hypotenuse)
We can use the Pythagorean theorem
a^2+b^2 = c^2 where a and b are the legs and c is the hypotenuse
80^2 + 60^2 = c^2
6400+3600 = c^2
10000 = c^2
Taking the square root of each side
sqrt(10000) = sqrt(c^2)
100 = c
