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2 years ago

Find the value of x. Enter your answer as a number

Mathematics

1 answer:

tensa zangetsu [6.8K]2 years ago

8 0

A whole circle is 360 degrees. So add up the known degrees (115+105+60)=280degrees
Then 360-280=80 degrees

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Plz help me fast plz plz plz thank you 15 points plZ help

bogdanovich [222]

Answer:

Possible Outcomes = {January , February, March, April,May, June, July, August, September , October , November ,December}

Explanation:

In probability The possible outcomes is a possible result of an experiment which we are performing. Each possible outcome is unique for a particular experiment

Now in this problem we are performing the experiment of putting the names of months in bag

Total months are 12

which are January , February, March, April,May, June, July, August, September , October , November and December

Now

Possible Outcomes = {January , February, March, April,May, June, July, August, September , October , November ,December}

So these are the possible results which can occur in our experiment that which ever we will pick the answer will be one of these 12 names

4 0

3 years ago

40 POINTS! HELP ME. QUICKLY.

dybincka [34]

Answer:

Part A: D,E

Part B:

m°= 90°

x°= 70°

y°= 70°0

z°= 110°

7 0

2 years ago

PLEASE HELP!! Will give brainliest if you give explanation!

MArishka [77]

The equation in slope-intercept is y=0.625x+7.

y = mx + b

where:
m is the slope of the line
b is the y-intercept of the line

The slope m of the line through any two points (x1, y1) and (x2, y2) is given by:

The y-intercept b of the line is the value of y at the point where the line crosses the y axis. Since for point (x1, y1) we have y1 = mx1 + b, the y-intercept b can be calculated by:

b = y1 - mx1. hope that helped

3 0

4 years ago

Using the bijection rule to count binary strings with even parity.

AleksandrR [38]

Answer:

Lets denote c the concatenation of strings. For a binary string a in B9, we define the element f(a) in E10 this way:

f(a) = a c {1} if a has an odd number of 1's
f(a) = a c {0} if a has an even number of 1's

Step-by-step explanation:

To show that the function f defined above is a bijective function, we need to prove that f is well defined, injective and surjective.

f is well defined:

To see this, we need to show that f sends elements fromo b9 to elements of E10. first note that f(a) has 1 more binary integer than a, thus, it has 10. if a has an even number of 1's, then f(a) also has an even number because a 0 was added. On the other hand, if a has an odd number of 1's, then f(a) has one more 1, as a consecuence it will have an even number of 1's. This shows that, independently of the case, f(a) is an element of E10. Thus, f is well defined.

f is injective (or one on one):

If a and b are 2 different binary strings, then f(a) and f(b) will also be different because the first 9 elements of f(a) form a and the first elements of f(b) form b, thus f(a) is different from f(b). This proves that f in injective.

f is surjective:

Let y be an element of E10, Let x be the first 9 elements of y, then f(x) = y:

If x has an even number of 1's, then the last digit of y has to be 0, and f(x) = x c {0} = y
If x has an odd number of 1's, then the last digit of y has to be a 1, otherwise it wont be an element of E10, and f(x) = x c {1} = y

This shows that f is well defined from B9 to E10, injective, and surjective, thus it is a bijection.

3 0

3 years ago

12.125 rounded to the nearest tenth.

nika2105 [10]

Answer: 12.1
Look at the hundredth place for rounding to tens and since it is less than 5 you drop the following numbers and keep the 1
:)

8 0

3 years ago