There is a 0.9968 probability that a randomly selected 50-year-old female lives through the year (based on data from the U.S. Department of Health and Human Services).
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A Fidelity life insurance company charges $226 for insuring that the female will live through the year. If she does not survive the year, the policy pays out $50,000 as a death benefit.
From the perspective of the 50-year-old female, what are the values corresponding to the two events of surviving the year and not surviving?
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Ans: -226 ; 50,000-226 = 49774
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If a 50-year-old female purchases the policy, what is her expected value?
WORK TRIED:
In the event she lives, the value is -$226. In the event she dies, the value is $49,774.
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E(x) = 0.9968*(-226) + 0.0032(49774) = -$66
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Cheers,
ROR
Answer:
b = -27
Step-by-step explanation:
-1/3 b = 9
Multiply each side by -3
-3 * -1/3 b = -3 * 9
b = -27
Answer:
The answer is B.
Step-by-step explanation:
Hope it helps!!
John sold 18 general admission tickets and 11 VIP tickets.
Step-by-step explanation:
Given,
Cost of each general admission = $50
Cost of each VIP ticket = $55
Total tickets sold = 29
Total revenue generated = $1505
Let,
x represent the number of general admission tickets sold
y represent the number of VIP tickets.
x+y=29 Eqn 1
50x+55y=1505 Eqn 2
Multiplying Eqn 1 by 50

Subtracting Eqn 3 from Eqn 2

Dividing both sides by 5

Putting y=11 in Eqn 1

John sold 18 general admission tickets and 11 VIP tickets.
Keywords: linear equation, elimination method
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<span>1. Let t = time in years, with t = 0 representing the year 2005. Let f(t) = the number of students enrolled at the private school and g(t) = the number of students enrolled at the public school. Create the two functions to represent the situation.
f(t) = 85 + 18t </span>⇒ y = 85 + 18x<span>
g(t) = 95 + 15t </span>⇒ y = 95 + 15x
y = y
85 + 18x = 95 + 15x
18x - 15x = 95 - 85
3x = 10
x = 10/3
x = 3 1/3
y = 85 +18(10/3) = 85 + 180/3 = 85 + 60 = 145
y = 95 + 15(10/3) = 95 + 150/3 = 95 + 50 = 145
x = 10/3 or 3 1/3
y = 145