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3 years ago

7. Find the volume of an aquarium

Mathematics

1 answer:

solong [7]3 years ago

8 0

Answer: 1200 cubic inches

Step-by-step explanation: volume = L x W x H

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If three sides of a right triangle are 10, 45, and 42, which side is the hypotenuse?

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Step-by-step explanation:

The hypotenuse is always the longest side.

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3 years ago

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KRISTIN SPENT 40$ on diapers. 8$ / package , how many packages did she buy

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3 years ago

A rectangle has a length that is 18 feet more than the width. The area of the

Archy [21]

Answer:

For a rectangle of length L and width W, the area is:

A = L*W

In this case, we know that;

The length is 18ft more than the width.

L = W + 18ft

The area is 175 ft^2

Then:

A = 175 ft^2

Then we have a system of two equations:

L = W + 18ft

A = L*W = 175 ft^2

To solve this, the first step would be to replace the first equation into the second one:

(18ft + W)*W = 175ft^2

Now we can solve this for W.

18ft*W + W^2 - 175ft^2 = 0.

This is the quadratic equation, i will solve it just to be complete.

We have a quadratic equation, using the Bhaskara formula we can find the two solutions as:

$w = \frac{-18ft +- \sqrt{(18ft)^2 - 4*1*(-175ft^2)} }{2*1} = \frac{-18ft +- 32ft}{2ft}$

Then the two solutions are:

W = (-18ft - 32ft)/2 = -25ft (This option can be discarded, because a negative width has no sense)

W = (-18ft + 32ft)/2 = 7ft

Then the width is 7ft long, and the lenght will be:

L = W + 18ft = 7ft + 18ft = 25ft

3 0

3 years ago

Liam is putting up fence around a garden. He has poles located at A(7,7), B(16,7), C(2,2), D(16,2). Each unit on his coordinate

Bezzdna [24]

To find the amount of fencing needed, we will find tge perimeter

To find the perimeter;

Find the distance |AB|, |BC|, |CD| and |DA|

We will use the formula below to find the distances:

$|d|=\sqrt[]{(x_2-x_1)^2+(y_{2-}y_1)^2}$

Distance |AB|

A(7,7), B(16,7)

x₁=7 y₁=7 x₂=16 y₂=7

Substituting into the formula;

$|AB|=\sqrt[]{(16-7)^2+(7-7)^2}$ $=\sqrt[]{9^2+0}$

$=\sqrt[]{9}^2\text{ =9}$

Distance |BC|

B(16,7), C(2,2)

x₁=16 y₁=7 x₂=2 y₂=2

substituting into the formula;

$|BC|=\sqrt[]{(2-16)^2+(2-7)^2}$

$=\sqrt[]{(-14)^2+(5)^2}$ $=\sqrt[]{196+25}$

$=\sqrt[]{221}$ $=14.87$

Distance |CD|

C(2,2), D(16,2)

x₁=2 y₁=2 x₂=16 y₂=2

substituting into the formula;

$|CD|=\sqrt[]{(16-2)^2+(2-2)^2}$

$=\sqrt[]{14^2+0}$ $=\sqrt[]{14^2}=14$

Distance |DA|

D(16,2) A(7,7)

x₁=16 y₁=2 x₂=7 y₂=7

Substituting into the formula;

$|DA|=\sqrt[]{(7-16)^2+(7-2)^2}$

$=\sqrt[]{(-9)^2+(5)^2}$ $=\sqrt[]{81+25}$

$=\sqrt[]{106}=10.30$

Perimeter = |AB|+|BC|+|CD|+|DA|

= 9 + 14.87 + 14 + 10.30

=48.17

≈48

Hence;

48 feet of fencing is needed

8 0

1 year ago