All categories

3 years ago

Someone please help !!

Mathematics

1 answer:

vaieri [72.5K]3 years ago

8 0

Answer:

Step-by-step explanation:

138-88=50

You might be interested in

Interval Notation <br> Inequality Notation <br> Pls help

Andrew [12]

Step-by-step explanation:

Interval notation

$[ 10, +\infty \rang$

Inequality Notation

$x \geq 10$

4 0

3 years ago

5 points

noname [10]

Answer:

A. y=10x+50

Step-by-step explanation:

you only add $50 once because it is the "become a member fee", you put a X next to the 10 because its monthly. (so you can replace the variable with any number if needed)

6 0

3 years ago

The tortoise versus the hare: The speed of the hare is given by the sinusoidal function H(t) = sin(t) and the speed of the torto

nata0808 [166]

Answer:

b. The difference in the distance traveled by the tortoise and hare during that time.

Step-by-step explanation:

First the intersection points are found out on the graph. Then the area between the curves is found out.

Putting the values

H(t) = sin(t)

H(t) = sin(1) = 0.01745

T(t) = cos(t),

T(t) = cos(1)= 0.9998

As T(t) ≥ H(t)

Area is found out by taking the integral of it.

Area = Integral ( limit 0 to 0.998) T(t)-H(t) dt

The difference represents how far the turtle is from the hare.

So it represents the difference in the distance traveled by the tortoise and hare during that time.

4 0

3 years ago

Prove that the sum of 3 consecutive numbers is always a multiple of 3

Bad White [126]

Proof:

3 consecutive integers are x, x+1 , x+2.

Add these values.

x+x+1+x+2

3x+3

3×(x+1)

3(x+1) is the multiple of 3 for any integer value of x.

7 0

4 years ago

A friend who works in a big city owns two cars, one small and one large. One-quarter of the time he drives the small car to work

lubasha [3.4K]

Answer:

The probability that he drove the small car is 0.318.

Step-by-step explanation:

We are given that a friend who works in a big city owns two cars, one small and one large. One-quarter of the time he drives the small car to work, and three-quarters of the time he takes the large car.

If he takes the small car, he usually has little trouble parking and so is at work on time with probability 0.7. If he takes the large car, he is on time to work with probability 0.5.

Let the Probability that he drives the small car = P(S) = $\frac{1}{4}$ = 0.25

Probability that he drives the large car = P(L) = $\frac{3}{4}$ = 0.75

Also, let WT = event that he is at work on time

So, Probability that he is at work on time given that he takes the small car = P(WT / S) = 0.7

Probability that he is at work on time given that he takes the large car = P(WT / L) = 0.5

Now, given that he was at work on time on a particular morning, the probability that he drove the small car is given by = P(S / WT)

We will use the concept of Bayes' Theorem for calculating above probability;

So, P(S / WT) = $\frac{P(S) \times P(WT/S)}{P(S) \times P(WT/S)+P(L) \times P(WT/L)}$

= $\frac{0.25 \times 0.7}{0.25 \times 0.7+0.75 \times 0.5}$

= $\frac{0.175}{0.55}$

= <u>0.318</u>

Hence, the required probability is 0.318.

8 0

3 years ago