58=y=39
(subtract 39 from both sides)
58-39=y
(simplify 58-39 to 19)
19=y
(switch sides)
y=19
Answer:
C (11.3) = 165
P (3,3) = 6
Step-by-step explanation:
We want to select 3 players out of 11 regardless of the order. That is, there is no difference between selecting the players {2,5,7} or {7,2,5}
Then we use the formula of combinations:
![C(n, r) = \frac{n!}{r!(n-r)!}\\\\C(11, 3) = \frac{n!}{r!(n-r)!}\\\\C(11, 3) = 165](https://tex.z-dn.net/?f=C%28n%2C%20r%29%20%3D%20%5Cfrac%7Bn%21%7D%7Br%21%28n-r%29%21%7D%5C%5C%5C%5CC%2811%2C%203%29%20%3D%20%5Cfrac%7Bn%21%7D%7Br%21%28n-r%29%21%7D%5C%5C%5C%5CC%2811%2C%203%29%20%3D%20165)
There are 165 ways to choose 3 players out of 11.
Now we want to know how many ways you can designate those 3 players as first, second and third. Now if we care about the order of selection. Then we use permutations.
![P(n, r) = \frac{n!}{(n-r)!}\\\\P(3,3) = \frac{3!}{(3-3)!}\\\\P(3,3) = 6](https://tex.z-dn.net/?f=P%28n%2C%20r%29%20%3D%20%5Cfrac%7Bn%21%7D%7B%28n-r%29%21%7D%5C%5C%5C%5CP%283%2C3%29%20%3D%20%5Cfrac%7B3%21%7D%7B%283-3%29%21%7D%5C%5C%5C%5CP%283%2C3%29%20%3D%206)
They can be designated in 6 different ways
Answer:
The two objects are similar because of their gcf
Given 17 books.
Total 56 b<span>ooks.
How many books were in her collection before her teachers donation?
</span>
First lets write an equation:
b = books before
17 + b = 56
Lets solve for b:
17 + b = 56
Inverse Operation:
56 - 17 = b
56 - 17 = 39
b = 39
Check:-
17 + b = 56
17 + 39 = ?
17 + 39 = 56
Correct!
There were 39 books in her collection before her teacher donated her books.
The equation is: 17 + b = 56.
b = 39
The correct option would be: y = 2x
You can check by replacing the variables with the given values.
Hope this helps!