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Scorpion4ik [409]
3 years ago
7

PLEASE HELPP

Mathematics
2 answers:
agasfer [191]3 years ago
6 0

Answer:

The solution to the system of equations be:

x=3,\:y=-1

Hece, option B is correct.

Step-by-step explanation:

Given the system of equations

\begin{bmatrix}x-3y=6\\ 2x+2y=4\end{bmatrix}

Multiply x − 3y = 6 by 2:      2x-6y=12

\begin{bmatrix}2x-6y=12\\ 2x+2y=4\end{bmatrix}

so

2x+2y=4

-

\underline{2x-6y=12}

8y=-8

so the system of equations becomes

\begin{bmatrix}2x-6y=12\\ 8y=-8\end{bmatrix}

Solve 8y = -8 for y

8y=-8

Divide both sides by 8

\frac{8y}{8}=\frac{-8}{8}

y=-1

\mathrm{For\:}2x-6y=12\mathrm{\:plug\:in\:}y=-1

2x-6\left(-1\right)=12

2x+6=12

subtract 6 from both sides

2x+6-6=12-6

2x=6

Divide both sides by 2

\frac{2x}{2}=\frac{6}{2}

x=3

Therefore, the solution to the system of equations be:

x=3,\:y=-1

Hence, option B is correct.

Murljashka [212]3 years ago
3 0
<h2><u>A</u><u> </u><u>N</u><u> </u><u>S</u><u> </u><u>W</u><u> </u><u>E</u><u> </u><u>R</u><u> </u><u>:</u></h2>

  • x - 3y = 6 ......[Equation (i) ]
  • 2x + 2y = 4 ......[Equation (ii)]

<u>⚽</u><u> </u><u>From</u><u> </u><u>Equation</u><u> </u><u>(</u><u>i</u><u>)</u><u> </u><u>we </u><u>get</u><u> </u><u>:</u>

  • x = 6 + 3y......[Equation (iii)]

<u>⚽</u><u> </u><u>Now</u><u>,</u><u> </u><u>Substitut</u><u>e</u><u> </u><u>the</u><u> </u><u>equat</u><u>ion</u><u> </u><u>(</u><u>iii</u><u>)</u><u> </u><u>in</u><u> </u><u>eq</u><u>uation</u><u> </u><u>(</u><u>ii</u><u>)</u><u> </u><u>we</u><u> </u><u>get</u><u> </u><u>:</u>

→ 2(6 + 3y) + 2y = 4

→ 12 + 6y + 2y = 4

→ 8y = 4 - 12

→ 8y = -8

→ y = -8 ÷ 8

→ y = -1

<u>⚽</u><u> </u><u>Now</u><u> </u><u>Substituting</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>y</u><u> </u><u>=</u><u> </u><u>-</u><u>1</u><u> </u><u>in</u><u> </u><u>e</u><u>quation</u><u> </u><u>(</u><u>iii</u><u>)</u><u> </u><u>we</u><u> </u><u>get</u><u> </u><u>:</u>

→ x = 6 + 3y

→ x = 6 + 3(-1)

→ x = 6 + (-3)

→ x = 6 - 3

→ x = 3

  • <u>Hence</u><u>,</u><u>the </u><u>value</u><u> </u><u>of</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>3</u><u> </u><u>and</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>y</u><u> </u><u>=</u><u> </u><u>-</u><u>1</u><u>.</u>
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