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Liono4ka [1.6K]

3 years ago

8

10 points for correct answer

1 answer:

PolarNik [594]3 years ago

7 0

Correct answer is b
Hope thsi helps give me brainliest

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irina [24]

Answer: Divergent

Explanation:

4 0

3 years ago

How does the Köppen system classify different climate zones?

soldi70 [24.7K]

Answer:

The Koppen climate classification system is based on design of the botanist an is based on the type of the vegetation gown in different regions.

Explanation:

The Köppens climatic classification system is based on the five major class and groups, them with each of them being based on the seasonal rainfall and the temperature patterns of the places.

These five groups are then as A (tropical), B as (dry), the C as (temperate), the D as (continental), and the E as (polar).

Each group and subgroup is shown by a letter that symbolizes them. His classification has been further modified by the Trewartha climatic classification of the 1960's.

5 0

3 years ago

Star A and star B appear equally bright in the sky, Star Ais 5 times as far away from Earth as star B. This means that star A is

daser333 [38]

This means that star A is 5 times as luminous as star B

5 0

3 years ago

Read 2 more answers

While political borders often ignore tribal boundaries, differing tribal Ghanans were able to use unite under?

Helen [10]

<span>the answer is pan-</span>Africanism

6 0

3 years ago

2. If both the mass and radius of the earth, each decreases by 50%, the acceleration due to gravity would (a) remain same (b) de

Scrat [10]

Answer:

(d) increase by 100%

Explanation:

$m_{i}$ = initial mass of earth = m

$m_{f}$ = final mass of earth = (0.5) m

$R_{i}$ = initial radius of earth = R

$R_{f}$ = final radius of earth = (0.5) R

$g_{i}$ = initial acceleration due to gravity of earth = g

$g_{f}$ = final acceleration due to gravity of earth

initial acceleration due to gravity of earth is given as

$g_{i} = \frac{Gm_{i}}{R_{i}^{2}}$ Eq-1

Final acceleration due to gravity of earth is given as

$g_{f} = \frac{Gm_{f}}{R_{f}^{2}}$ Eq-2

Dividing eq-1 by eq-2

$\frac{g_{i}}{g_{f}} = \frac{m_{i}}{m_{f}}\frac{R_{f}^{2}}{R_{i}^{2}}$

inserting the values

$\frac{g}{g_{f}} = \frac{m_{i}}{(0.5)m_{i}}\frac{(0.5)^{2}R_{i}^{2}}{R_{i}^{2}}$

$g_{f}$ = 2 g

So there is 100% increase

8 0

3 years ago