Answer:
29.4 meters
Step-by-step explanation:
Given the following :
A submarine ascended from 56.8 meters under the sea level to 27.4 meters under the sea level.
distance it moved between two positions. Use the "distance on the number line "formula
Initial Position or distance of submarine before ascension = 56.8 meters
Final position after ascension = 27.4 meters
The distance moved by the submarine between the two positions can be obtained by.
(Initial distance - Final distance)
(56.8 - 27.4) = 29.4 meters
Answer:
75%
Step-by-step explanation:
Percent means out of 100
so 100-25= 75
I think the answer would be $9.46 left as a tip for the waiter.
Given that Allison’s dog is 6 pounds more than 5 times the weight of Gail’s dog, it is important to know the following:
1. The word "more" indicates an Addition.
2. The word "times" indicates Multiplication.
Knowing this, you can write the following expression to represent "5 times the weight of Gail’s dog", where "g" is the weight of Gail’s dog:
Therefore, you can determine that the weight of Allison's dog (in pounds) is the sum of 6 pounds and 5 times the weight of Gail's dog (in pounds). Then, you can represent this with this algebraic expression:
Hence, the answer is:
Subtract the sides of the equation minus 3
Divided the sides of the equation by 2
So ;
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And we're done.
Thanks for watching buddy good luck.
♥️♥️♥️♥️♥️
