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Cerrena [4.2K]
3 years ago
11

4) Solve the inequality: -10m > 70

Mathematics
1 answer:
den301095 [7]3 years ago
8 0

Answer:

m < 7

Step-by-step explanation:

-10m>70

-m>7

m<7

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An elevator has a maximum weight limit of 1.5 tons .Rozell company workers load boxes that weight 150 each into the elevator to
FrozenT [24]

Answer:

Total no of 9 boxes can be transported in the elevator with capacity of 1.5 ton and each box of 150kg each

Step-by-step explanation:

To calculate the greatest number of boxes the elevator can hold first we will find the total capacity of elevator in kgs

maximum weight capacity of the elevator= 1.5 tons

as 1 ton = 907.185 kgs

so 1.5 ton = 1.5 x 907.185 kgs

                 = 1360.78 kg

The formula which will be used is

Total capacity of the lift = no of boxes x weight of each box

to find no of boxes we will re arrange the equation

No of Boxes = Total capacity of the lift/  weight of each box

No\,of\,\,boxes= \frac{1360.78}{150} \\                         = 9.07185\\

So total no of 9 boxes can be transported in the elevator with capacity of 1.5 ton and each box of 150kg each

Keywords: Arithmetic

Learn more about Solving Linear System at:

  • monroecc.edu
  • aptitude-test.com/basic-arithmetic.html

#learnwithBrainly

3 0
3 years ago
Can someone please answer this question I need it today please show work and please answer it correctly i
svlad2 [7]

Answer:

24) $495

25) 14%

26) 25/X = 83/100

27) 0.7p

28) x + .085x and 1.085x

29) $221.90

30) $24.10

31) $6.13

32) 40%

Step-by-step explanation:

24) 600 - (600 × 0.25) = 450

450 × 1.10 = 495

25) (106 - 93) ÷ 93 = 0.13978

0.13978 × 100 = 13.978 ~ 14

27) 1.0 - 0.3 = 0.7

28) 1.00 + 0.085 = 1.085

29) 100% - 15% = 85%

240 × 0.85 = 204

204 × 1.0875 = 221.85

30) 25.89 × 4 = 103.56

103.56 + 179.99 = 283.55

283.55 × 0.085 = 24.10175

31) 8.75 × 0.70 = 6.125

32) 80 - (80 × 0.40) = 48

4 0
3 years ago
The frequency table below displays 17 students'
vazorg [7]
Yes, because the data can be displayed by a relative frequency compared with the whole.
3 0
3 years ago
PLEASE HELP
Sholpan [36]
1) We have that the equation is x^2=20y , hence y=x^2/20. The standard equation of such an equation is y=\frac{1}{4p} x^2. Hence, p=5 in this case. The focus is at (0,5) and the directrix is at y=-5 (a tip is that the directrix is always "opposite" the focus point of a parabola; if the directrix is at x=-7 for example, the focus is at (7,0)).
2) Similarly, we have that the equation is x=3y^2 \\  \frac{1}{4p} =3. Thus, p=1/12. In this case, the parabola opens along the x-axis and the focus is at (1/12, 0). Also, the directrix is at x=-1/12. Hence the correct answer is B.
3) We are given that the parabola has a p of 9. Also, the focus lies along the y-axis, hence the parabola is opening along the y-axis. Finally, the focus is on the positive half, so the parabola is opening upwards. The equation for this case is y=y=\frac{1}{4p} x^2= \frac{1}{36 } x^2.
4) Similarly as above. The directrix is superfluous, we only need the p-value. THe same comments about the parabola apply and if we substitute p=8 in the formula: y= \frac{1}{4p} x^2 we get y=\frac{1}{32} x^2.
5) This is somewhat different, even though we do not need the directrix again. The focus lies on the x-axis, thus the parabola opens in this direction. The focus lies on the positive part of the axis, thus the parabola opens to the right. We also are given p=7. Hence, the equation we need is of the formx= \frac{1}{4p} y^2. Substituting p=7, we get x= \frac{1}{28} y^2.
6) The equation of a prabola with a vertex at (0,0) is of the form y=-ax^2. The minus sign is needed since the parabola is downwards. Since we are given anothe point, we can calculate a. We have to take y=-74 and x=14 feet (since left to right is 28, we need to take half). -a= \frac{y}{x^2} = \frac{-74}{14^2} =-0.378. Thus a=0.378. Hence the correct expressions is y=-0.378*x^2
7 0
3 years ago
Read 2 more answers
Find the coordinates of the other endpoint of the​ segment, given its midpoint and one endpoint.​ (Hint: Let​ (x,y) be the unkno
spin [16.1K]
The other endpoint is (1, -17).

The midpoint formula is:

m=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})

Using our midpoint and endpoint, we have:
(6, -11) = (\frac{11+x_2}{2}, \frac{-5+y_2}{2})&#10;\\&#10;\\6=\frac{11+x_2}{2} \text{ and } -11=\frac{-5+y_2}{2}&#10;

For the first equation (to find the x-coordinate) we will multiply both sides by 2:
6\times2=\frac{11+x_2}{2}\times 2&#10;\\&#10;\\12=11+x_2

Subtract 11 from both sides:
12 - 11 = 11+x₂ - 11
1 = x₂

For the second equation (the y-coordinate) we multiply both sides by 2:
-11\times2=\frac{-5+y_2}{2}\times 2&#10;\\&#10;\\-22=-5+y_2

Add 5 to both sides:
-22+5 = -5+y₂ + 5
-17 = y₂

This means that (x₂, y₂) is at (1, -17).
4 0
3 years ago
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