Let Marc's age be x. If Jeanine is twice as old as Marc, then her age will be 2x. If their ages added together are 24, then you can create the following equation:
2x + x = 24
3x = 24
x = 8
Remember that x is Marc's age. So if Marc is 8, and Jeanine is twice as old, she will be 16.
C
First you -4 from x so you have to do the opposite which is to add 4
It is...........
2.789=2 ones and 7 tenths 8 hundreths 9 thousandths
Answer:
hello the correct answer is y=30x+20
Step-by-step explanation:
Answer:
14.1
Step-by-step explanation:
