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3 years ago

A and b are integers.

Mathematics

1 answer:

GREYUIT [131]3 years ago

8 0

Answer:

a is -9

b is 4

Step-by-step explanation:

we know that a and b are whole numbers.

we know that they are factors of 36.

1 * 36

2 * 18

3 * 12

4 * 9

6 * 6

i just did this as guess and check.

what numbers have a difference of 5?

the factors 4 and 9.

so, if a is the negative one, a has to be -9 to get -5 because

-9 + 4 = -5

and

(-9)(4) = 36

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Xavier writes a ratio out of 18 as the decimal 0.22222222.

Digiron [165]

Answer: 4/18

Step-by-step explanation:

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3 years ago

Becky Anderson must pay a lump sum of $6000 in 5 yr. If only $5000 is available to deposit right now, what annual interest rate

34kurt

Hello!

Out equation is: $A=P(1+\frac{r}{n} )^t^n$

A= 6000

P=5000

N=1

T=5

R= What we are trying to find

This means we will have $6000=5000(1+r)^5$

Divide both sides by 5000:

$\frac{6000}{5000} = (1+r)^5$

Move the power to the other side by rooting both sides:

$\frac{6000}{5000} ^1^/^5 = 1+r$

Subtract 1 from both sides:

$\frac{6000}{5000} ^1^/^5 -1 = r$

Now we just need to calculate: R = 0.03713728...

I don't know how many decimal places you can have, but I will round to 2. This will give you an Interest Rate of 3.71%.

I hope this helps! :)

6 0

3 years ago

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Please help ASAP 26 pts + brainliest to right/best answer

sergejj [24]

Answer:

d power property

Step-by-step explanation:

log (125x^3) ^ 1/12

log (5^3x^3) ^ 1/12

log (5x)^3 ^ 1/12

We use the power property to rewrite

a^b^c as a^ (b*c)

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log (5x) ^ 1/4

This is equal to

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3 years ago

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jok3333 [9.3K]

The equation $x^2-9y^2=900$ defines a hyperbolic cylinder.

1. Divide the equation $x^2-9y^2=900$ by 900:
$\dfrac{x^2}{900} - \dfrac{y^2}{100} =1$ .
This is the equation of conic section when z=0 (or z=const) and that is hyperbola equation.

2. To find the domain and the range you should express y:
$\dfrac{y^2}{100} =\dfrac{x^2}{900} - 1 \\ \\ y^2= \dfrac{x^2}{9} -100 \\ \\ y=\pm \sqrt{\dfrac{x^2}{9} -100}$ .
Since you have square root,
$\dfrac{x^2}{9} -100\ge 0 \\ x^2-900\ge 0 \\ (x-30)(x+30)\ge 0 \\ x\in(-\infty,-30)\cup (30,\infty)$ . This is the domain, the range is $y\in (-\infty,\infty)$ .

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3 years ago

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Ede4ka [16]

turn it to a decimal and see

#1 False

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#2

0.428571≠0.375

False

#3

0.428571≠0.4375

False

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3 years ago

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