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SVETLANKA909090 [29]
3 years ago
6

Please help me with this question!!

Mathematics
1 answer:
lidiya [134]3 years ago
4 0

Answer:

Step-by-step explanation:

Mabye 7?

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How many times does the graph of 4x = 32 - x2 cross the x-axis?<br><br> 0<br><br> 1<br><br> 2
Yakvenalex [24]

Answer:

2

Step-by-step explanation:

4x = 32 - x2 would be much clearer if written as 4x = 32 - x^2.  Please use

" ^ " to indicate exponentiation.

Rewrite 4x = 32 - x^2 in the standard form of a quadratic:  x^2 + 4x - 32

Then the coefficients are a = 1, b = 4 and c = -32.

Find the discriminant.  It is b^2-4ac.  

Here, b^2-4ac = 4^2 - 4(1)(-32), or 16 + 128, or 144.

Because the discriminant is positive, we know immediately that this quadratic has two real, unequal roots.

So, the answer to this question is "the graph of 4x = 32 - x^2 cross the x-axis in two places."

4 0
4 years ago
Read 2 more answers
10.5% of the population is 65 or older. Find the probability that the following number of persons selected at random from 25 peo
julia-pushkina [17]

Given:

The sample size n=25

Probability of population is 65 or older is 10.5%.

This date follows the binomial distribution,

\begin{gathered} n=25,p=0.105 \\ X\rightarrow B(n=25,p=0.105) \end{gathered}

To find the probability that at most 2 are 65 or older,

\begin{gathered} P(X=x)=^nC_x(p)^x(1-p)^{n-x} \\ P(0\leq X\leq2)=P(X=0)+P(X=1)+P(X=2) \\ =^{25}C_0(0.105)^0(1-0.105)^{25-0}+^{25}C_1(0.105)^1(1-0.105)^{25-1}+^{25}C_2(0.105)^2(1-0.105)^{25-2} \\ =0.0625+0.1832+0.2579 \\ =0.5036 \\ \approx0.504 \end{gathered}

Answer: Probability is 0.504 .

8 0
1 year ago
(24-2)180 whats the answer?
Nookie1986 [14]

Answer:

3960 is the answer

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Isabel wrote this mystery problem. The quotient is multiple of 6. The dividend is multiple of 9. The divisor is a factor of 12.
Marina86 [1]

Answer:

Consider the expression q=\frac{a}{b}. q is called the quotient, a is is the dividend and b is the divisor.

Since q is a multiple of 6, then q has the form q=6k for some integer k.

Since a is a multiple of 9, then a has the form a=9s for some integer s.

Since b is a factor of 12, then if 12 can be expressed of the form 12=c*b, for c an integer. Then b has the form b=\frac{12}{m}

Replacing the preview expression in the initial expression we obtain:

6k=\frac{9s}{\frac{12}{m}}=\frac{9sm}{12}\\6*12k=9sm\\72k=9sm\\72k-9sm=0

Then 72k-9sm=0,\; for \; k,s,m\in \mathbb{Z} is a equation to Isabel's problem.

3 0
3 years ago
Help with this question anyone?
Art [367]
Adding 49 will explain it properly just do that and you will get the answers
6 0
3 years ago
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