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goblinko [34]
3 years ago
14

Endpoint (-2,-6), midpoint (9,-10)

Mathematics
1 answer:
Marina86 [1]3 years ago
5 0

Answer:   fined  the parabola through (9,-10) with vertex ( -2, -6 ) using the vertex from y=a(x -h) +k.

standard from y=- 4/121 x2 -16/121 x -742/121

vertex from: y= - 4/121 (x+2)2-6

      hope this helps :)

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Solve the following equation for y. Assume that b and y are non-zero real numbers. show and explain your work.
MA_775_DIABLO [31]
6-by=19
minus 6 from both sides
-by=19-6
-by=13
divide both sides by -b
y=13/-b
y=-13/b
5 0
3 years ago
-6(1+7x)+7(1+6x)=-2​
-BARSIC- [3]

-6(1+7x)+7(1+6x)=-2​

This is False.

Use distributive property:

-6 -42x + 7 +42x = -2

Combine like terms to get:

1 = -2

Since 1 is not -2, it is false.

8 0
4 years ago
Choosy Chocolates sold chewy squares and chocolate stars at a ratio of 3 to 8. 45 more chocolate stars were sold than chewy squa
masya89 [10]
So 45 more chocolate stars were sold compared to chewy squares, which makes it a ratio of 3:8, hence we can assume that (45÷5=9) is the amount sold for each ratio.

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3 0
4 years ago
43 points, 86 for brainliest! Answer correct!! Be wise! Acording to the image attached, whats the answer?
Dvinal [7]

Answer:

c = 62.83 ft

a = 314.159 {ft}^{2}

Step-by-step explanation:

c = 2\pi \: r \\ c = 2 \times \pi \times 10 \\ c = 62.83ft

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8 0
4 years ago
Read 2 more answers
Which compound inequality has no solution?
vazorg [7]

Answer: The first option:

x ≤ -2  and 2x ≥ 6

Step-by-step explanation:

A compound inequality will have no solution if the inequalities are contradictory.

An example of this would be:

x > 3 and x < 1

There is no value of x that is at the same time larger than 3, and smaller than 1.

Now, let's analyze the options.

1) x ≤ -2  and 2x ≥ 6

This has no solution, because if x ≥ -2, the maximum value that x can take is x = -2

Replacing that in the other inequality we get:

2*(-2) > 6

-4 > 6

This is false, then this compound inequality has no solution.

2) x ≤ -1  and 5*x < 5

This ineqalty has infinite solutions, one can be x = -2

-2 ≤ -1 and 5*(-2) < 5

are both true.

3) x ≤ -1 and 3x ≥ -3

A solution for this can be x = -1

-1 ≤ -1  is true

3*(-1) ≥ -3

-3 ≥ -3 is true.

Then we have at least one solution here.

4) x ≤ -2  and 4x ≤ -8

Here we have infinite solutions, one can be x = -10

-10 ≤ - 2 is true

4*(-10) ≤ -8

-40 ≤ - 8 is also true.

Then the only option that has no solutions is the first one.

6 0
3 years ago
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