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3 years ago

OMG PLEASE HELP PLEASE OMG HELP ME HELP PLZ!!!!!!!!!! HELPPPPPPPPPPPPp

Mathematics

1 answer:

ivann1987 [24]3 years ago

3 0

17.5 mark brainlist plssssssssssssss

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What is 123 as a percent????

Anarel [89]

Answer:

12,300%

Step-by-step explanation:

7 0

3 years ago

Describe the relationship between the perimeter of a triangle and the perimeter of the triangle that is formed by the midsegment

lilavasa [31]

It is 1/4 of the area of the larger triangle...basically if you connect the three midpoints of the triangle's sides it creates four identical smaller triangles...

The perimeter is one half of the larger triangle...

3 0

3 years ago

2/7 divided by 1/2 as a mixed number

Readme [11.4K]

Answer:

4/7

Step-by-step explanation:

2/7 ÷1/2=2/7 × 2 = 4/7

Hope this helps :D

8 0

3 years ago

Janice used a 16-inch dowel and a 21-inch dowel to build a kite what is the perimeter of her kite

marusya05 [52]

16x2=32
21x2=42
32+42=54

the perimeter is 54

6 0

3 years ago

Consider a large shipment of 400 refrigerators, of which 40 have defective compressors. If X is the number among 15 randomly sel

Vlad [161]

Answer:

The required probability is 0.94

Step-by-step explanation:

Consider the provided information.

There are 400 refrigerators, of which 40 have defective compressors.

Therefore N = 400 and X = 40

The probability of defective compressors is:

$\frac{40}{400}=0.10$

It is given that If X is the number among 15 randomly selected refrigerators that have defective compressors,

That means n=15

Apply the probability density function.

$P(X=x)=^nC_xp^x(1-p)^{n-x}$

We need to find P(X ≤ 3)

$P(X\leq3) =P(X=0)+P(X=1)+P(X=2)+P(X=3)\\P(X\leq3) =\frac{15!}{15!}(0.1)^0(1-0.1)^{15}+\frac{15!}{14!}(0.1)^1(1-0.1)^{14}+\frac{15!}{13!2!}(0.1)^2(1-0.1)^{13}+\frac{15!}{12!3!}(0.1)^3(1-0.1)^{12}\\$

$P(X\leq3) =0.944444369992\approx 0.94$

Hence, the required probability is 0.94

4 0

3 years ago