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3 years ago

The diameter of a circle is 10 cm. Find its circumference in terms of pi.

Mathematics

1 answer:

Annette [7]3 years ago

5 0

62.82 cm

Step-by-step explanation:

the formula of circumference of circle is 2 Pi R

so, 2 * 22/7 * 10 cm = 62.82 cm

You might be interested in

Eva earns $5.50 per hour and time-and-a-half for overtime for all hours over 40 hours. How much did she earn the week she worked

Morgarella [4.7K]

Answer:

$277.75

5.50×40=220

5.50÷2=2.75

5.50+2.75=8.25×7=57.75

57.75+220=277.75

5 0

2 years ago

The first equation in the system models the height in feet, h, of a falling baseball as a function of time, t. the second equati

Sonja [21]

The height of the baseball is 6 feet at the moment the player begins to leap. Then the correct option is D.

<h3>What is a function?</h3>

The function is an expression, rule, or law that defines the relationship between one variable to another variable. Functions are ubiquitous in mathematics and are essential for formulating physical relationships.

The first equation in the system models the height in feet, h, of a falling baseball as a function of time, t. the second equation models the height in feet, h, of the glove of a player leaping up to catch the ball as a function of time, t.

h(t) = 35 - 16t²

h(t) = 6 + 18t + 16t²

At t = 0, Then we have

h(0) = 35 - 16(0)²

h(0) = 35

And

h(0) = 6 + 18(0) + 16(0)²

h(0) = 6

The height of the baseball is 6 feet at the moment the player begins to leap.

More about the function link is given below.

brainly.com/question/5245372

4 0

3 years ago

The amount of money in dollars that Andrea makes is 16h+5, where h, represent the number of hours Andrea worked. Andrea hopes th

n200080 [17]

Answer:

It is possibly: 19h+28 and if she worked 6 hours after she got the raise she would earn $142.

Step-by-step explanation:

I’m not quite sure what you are asking but here my best answer:

$16 per hour plus an extra $3 from the raise. 16+3= 19. And $5+$23 in bonus earnings for $28. So the new equation for her earnings is; 19h+28. If she works 6 hours; 19 (6) +28. 19 times 6 is 114. 114+28=142.

3 0

3 years ago

Which equations are related equations to x + 5 = 34?

myrzilka [38]

Answer:

the answer is 5=34−x and x=34−5

Step-by-step explanation:

i just got finished taking the test in 7th grade k12

3 0

3 years ago

A shop sells a particular of video recorder. Assuming that the weekly demand for the video recorder is a Poisson variable with t

julia-pushkina [17]

Answer:

a) 0.5768 = 57.68% probability that the shop sells at least 3 in a week.

b) 0.988 = 98.8% probability that the shop sells at most 7 in a week.

c) 0.0104 = 1.04% probability that the shop sells more than 20 in a month.

Step-by-step explanation:

For questions a and b, the Poisson distribution is used, while for question c, the normal approximation is used.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\lambda}*\lambda^{x}}{(x)!}$

In which

x is the number of successes

e = 2.71828 is the Euler number

$\lambda$ is the mean in the given interval.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The Poisson distribution can be approximated to the normal with $\mu = \lambda, \sigma = \sqrt{\lambda}$ , if $\lambda>10$ .

Poisson variable with the mean 3

This means that $\lambda= 3$ .

(a) At least 3 in a week.

This is $P(X \geq 3)$ . So

$P(X \geq 3) = 1 - P(X < 3)$

In which:

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)$

Then

$P(X = x) = \frac{e^{-\lambda}*\lambda^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-3}*3^{0}}{(0)!} = 0.0498$

$P(X = 1) = \frac{e^{-3}*3^{1}}{(1)!} = 0.1494$

$P(X = 2) = \frac{e^{-3}*3^{2}}{(2)!} = 0.2240$

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0498 + 0.1494 + 0.2240 = 0.4232$

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 1 - 0.4232 = 0.5768$

0.5768 = 57.68% probability that the shop sells at least 3 in a week.

(b) At most 7 in a week.

This is:

$P(X \leq 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7)$

In which

$P(X = x) = \frac{e^{-\lambda}*\lambda^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-3}*3^{0}}{(0)!} = 0.0498$

$P(X = 1) = \frac{e^{-3}*3^{1}}{(1)!} = 0.1494$

$P(X = 2) = \frac{e^{-3}*3^{2}}{(2)!} = 0.2240$

$P(X = 3) = \frac{e^{-3}*3^{3}}{(3)!} = 0.2240$

$P(X = 4) = \frac{e^{-3}*3^{4}}{(4)!} = 0.1680$

$P(X = 5) = \frac{e^{-3}*3^{5}}{(5)!} = 0.1008$

$P(X = 6) = \frac{e^{-3}*3^{6}}{(6)!} = 0.0504$

$P(X = 7) = \frac{e^{-3}*3^{7}}{(7)!} = 0.0216$

Then

$P(X \leq 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) = 0.0498 + 0.1494 + 0.2240 + 0.2240 + 0.1680 + 0.1008 + 0.0504 + 0.0216 = 0.988$