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MAVERICK [17]
3 years ago
5

Can you please help

Mathematics
1 answer:
Dmitry [639]3 years ago
4 0

Answer is in the file below

tinyurl.com/wpazsebu

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Our equation for the height is:

y(t) = 275 - 16*t^2.

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-129.6 ft/s

The minus sign is because te pebble is falling down.

ii)  t1 = 4s, t2 = 4s + 0.05s = 4.05s

The average velocity is:

AV = \frac{(275 - 16*4.05^2) - (275 - 16*4^2)}{4.05 - 4} = \frac{16(4^2 - 4.05^2)}{0.05} = -128.8

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iii)  t1 = 4s, t2 = 4s + 0.01s = 4.01s

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The average speed is -128.16 ft/s.

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v(t) = dy(t)/dt.

v(t) = -2*16*t + 0

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v(4s) = -32*4 = -128

The instantaneous velocity at t = 4s is -128 ft/s.

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