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mixas84 [53]
3 years ago
12

Anyone know how to do this?

Mathematics
1 answer:
FinnZ [79.3K]3 years ago
5 0

Answer:

C.x^2+2x-2+\frac{3}{x-2}

Step-by-step explanation:

symbolab.com

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In ΔFGH, the measure of ∠H=90°, GF = 53, HG = 28, and FH = 45. What ratio represents the sine of ∠G?
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we have been given that in ΔFGH, the measure of ∠H=90°, GF = 53, HG = 28, and FH = 45. We are asked to find the ratio that represents the sine of ∠G.

First of all, we will draw a right triangle using our given information.

We know that sine relates opposite side of right triangle with hypotenuse.

\text{sin}=\frac{\text{Opposite}}{\text{hypotenuse}}

We can see from the attachment that opposite side to angle G is FH and hypotenuse is GF.

\text{sin}(\angle G)=\frac{FH}{GF}

\text{sin}(\angle G)=\frac{45}{53}

Therefore, the ratio \frac{45}{53} represents the sine of ∠G.

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